CODEWITHSUNDEEP
javajson
insomnium_
insomnium_

Reputation: 1820

String interpreted as Boolean

Here's my code:

try {
    BufferedReader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
    String temp = reader.readLine();
    if(temp!=null)
        result = new JSONObject(temp);
} catch (Exception e) {
    e.printStackTrace();
}

As you see, I assign String to String type object, but when code runs, result="true" and I get exception:

Value true of type java.lang.Boolean cannot be converted to JSONObject

That's frustrating.. should I cast or use .toString() for a String object? Why it's automatically converted to Boolean?

Update I've figured out, that this is not a Java issue, but JSONObject constructor is not receiving valid JSONObject.

Upvotes: 0

Views: 457

Answers (2)

user1271598
user1271598

Reputation:

"true" is not a JSONObject. A JSONObject is

an unordered collection of name/value pairs.

quoting from the same source as @devnull. Java is not interpreting the String result as a Boolean, rather the JSON value represented by the String "true" is correctly interpreted as a JSON boolean. Clearly, it is not a collection of name/value pairs, which is denoted as @Leos Literak suggested using curly braces, colons and semicolons:

{ key : "value"; otherkey : true }

I hope this helps. The term 'object' is used very differently in Java and JSON.

Upvotes: 2

devnull
devnull

Reputation: 123608

What you're observing is expected. Quoting from JSONObject:

Strings do not need to be quoted at all if they do not begin with a quote or single quote, and if they do not contain leading or trailing spaces, and if they do not contain any of these characters: { } [ ] / \ : , = ; # and if they do not look like numbers and if they are not the reserved words true, false, or null.

Upvotes: 2

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