CODEWITHSUNDEEP
sqlfirebirdclause
kudra
kudra

Reputation: 134

Which SQL clause should be used?

I have a table like this in Firebird:

Tablename: USERNAMES


+--------+-----+
|username|code |
+--------+-----+
|a       |1    |
+--------+-----+
|b       |2    |
+--------+-----+
|c       |3    |
+--------+-----+
|d       |4    |
+--------+-----+
|e       |5    |
+--------+-----+

and this table 

Tablename: SERVICES
+-----------+-----+-----+-----+
|serviceno  |user1|user2|user3|
+-----------+-----+-----+-----+
|v1         |     |1    |2    |
+-----------+-----+-----+-----+
|v2         |3    |2    |     |
+-----------+-----+-----+-----+
|v3         |5    |4    |     |
+-----------+-----+-----+-----+
|v4         |3    |2    |1    |
+-----------+-----+-----+-----+

I want that table as

    +-----------+-----+-----+-----+
    |serviceno  |user1|user2|user3|
    +-----------+-----+-----+-----+
    |v1         |     |a    |b    |
    +-----------+-----+-----+-----+
    |v2         |c    |b    |     |
    +-----------+-----+-----+-----+
    |v3         |e    |d    |     |
    +-----------+-----+-----+-----+
    |v4         |c    |b    |a    |
    +-----------+-----+-----+-----+

I've tried that

 SELECT IFF(A.USER1 = NULL,NULL,B.NAME),
    IFF(A.USER2 = NULL,NULL,C.NAME),
    IFF(A.USER3 = NULL,NULL,D.NAME)
     FROM SERVICES A INNER JOIN USERNAMES B ON (A.USER1 =B.CODE)
    INNER JOIN USERNAMES C ON (A.USER2 =C.CODE)
    INNER JOIN USERNAMES D ON (A.USER3 =D.CODE)

And several attempts too,but allways the result is only row v4. why? and how can i get all rows?

Upvotes: 1

Views: 101

Answers (3)

FrankPl
FrankPl

Reputation: 13315

You should use OUTER JOINS:

SELECT serviceno,
       IFF(A.USER1 = NULL,NULL,B.NAME),
       IFF(A.USER2 = NULL,NULL,C.NAME),
       IFF(A.USER3 = NULL,NULL,D.NAME)
 FROM SERVICES A
      LEFT OUTER JOIN USERNAMES B ON (A.USER1 =B.CODE)
      LEFT OUTER JOIN USERNAMES C ON (A.USER2 =C.CODE)
      LEFT OUTER JOIN USERNAMES D ON (A.USER3 =D.CODE)

An inner join only returns results if there is a match, and the result you want to have needs the rows even if user1, user2, or user3 is null, and hence there is no match between e. g. A and B.

And you can simplify that to

SELECT serviceno,
       B.NAME,
       C.NAME,
       D.NAME
 FROM SERVICES A
      LEFT OUTER JOIN USERNAMES B ON (A.USER1 =B.CODE)
      LEFT OUTER JOIN USERNAMES C ON (A.USER2 =C.CODE)
      LEFT OUTER JOIN USERNAMES D ON (A.USER3 =D.CODE)

Upvotes: 4

Joe
Joe

Reputation: 6827

I'm not familiar with Firebird, but here's a generic SQL solution:

select
    serviceno,
    (select username
       from usernames
      where services.user1 = usernames.code) as user1,
    (select username
       from usernames
      where services.user2 = usernames.code) as user2,
    (select username
       from usernames
      where services.user3 = usernames.code) as user3
from
    services

Upvotes: -1

Mihail Shishkov
Mihail Shishkov

Reputation: 15797

SELECT serviceno, u1.username as user1, u2.username as user2, u3.username as user3  FROM Services 
LEFT OUTER JOIN USERNAMES u1 ON user1 = u1.code 
LEFT OUTER JOIN USERNAMES u2 ON user2 = u2.code
LEFT OUTER JOIN USERNAMES u3 ON user3 = u3.code

Upvotes: 3

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