CODEWITHSUNDEEP
xcode
user3297482
user3297482

Reputation: 3

Xcode undefined symbols for architecture

Just started to teach OOP and have a weird error in my program, that looks like in my example. I'm using XCode and receive stange error :

Undefined symbols for architecture x86_64: "Foo::Foo()", referenced

using namespace std;

class Foo
{
    public:
        Foo();
        ~Foo();
        Foo(const Foo& f2);
        Foo(int data);
        Foo& operator =(const Foo& f2);
    protected:
        int m_Data;
};

Foo::Foo(int data)
{
    m_Data = data;
    cout << "constr1" << endl;
}

Foo::Foo(const Foo& f2)
{
    m_Data = f2.m_Data;
    cout << "constr2" << endl;
}

Foo::~Foo()
{
    cout << " destructor";
}

Foo& Foo::operator=(const Foo& f2)
{
    m_Data = f2.m_Data;
    cout << "prisvaivanie" << endl;
    return *this;
}

Foo test(Foo arg)
{
    return arg;
}

int main(int argc, const char * argv[])
{
    Foo f1(1);
    Foo f2(f1);
    Foo f3 = f1;
    Foo f4;
    f4 = f1;
    Foo f5 = test(f1);
    return 0;
}

What can it be?

Upvotes: 0

Views: 289

Answers (1)

Phillip Mills
Phillip Mills

Reputation: 31016

You declare a constructor that takes no parameters but don't define one and Foo f4; needs it.

Upvotes: 1

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