Java - Integer to 4 character Hex

Question

How Can I convert an integer into a 4 character hex number. I need the extra padding of 0s if it isnt long enough.

So 2 -> 0x0002, 18 -> 0x0012 etc

I am using Java

Answer 1

public static String toPaddedHex(int i) {
    return String.format("0x%04X", i);
}

Example:

System.out.println(toPaddedHex(123));

Prints:

0x007B

Answer 2

How about String.format("%04X", decInt);?

If you want to add 0x part just place it at start of pattern used in this method like String.format("0x%04X", decInt);