CODEWITHSUNDEEP
c#.netasp.net-mvcasp.net-mvc-4
Toubi
Toubi

Reputation: 2509

how to get model in custom model binder?

I m trying to create a custom model binder with below code:

public class TransactionModelBinder : IModelBinder
{
    public object BindModel(ControllerContext controllerContext,
        ModelBindingContext bindingContext)
    {
        Object Model = bindingContext.Model;

        //Do custom logic

        return Model;
    }
}

In global.asax, I m adding:

ModelBinders.Binders.Add(typeof(TransViewModel), new TransactionModelBinder());

Issue: I m not sure how to get Model. I tried bindingContext.Model but it is null. Please also guide if my line of code in Global.asax is fine.

Upvotes: 0

Views: 1610

Answers (2)

Pablo Romeo
Pablo Romeo

Reputation: 11406

Well, if you intend to write the entire binder from scratch, you will not have a model. Instead you'd actually be the one creating the model (since that's what the binder is for), from the form data. Such as:

return new SomeModel 
{
    OneProp = request.Form["OneProp"],
    AnotherProp = request.Form["AnotherProp"]
}

Alternatively you can inherit from DefaultModelBinder instead of IModelBinder, which you can use to extend only certain behavior instead of actually handling the construction of the model.

EDIT:

From your comments I'm understanding that you are only wanting to process one property in several viewmodels you might have (possibly multiple viewmodels have decimals that come from the view in a different format than what MVC expects for decimals.

In that case I'd actually use a different approach. Instead of registering the ModelBinder in global.asax, I'd remove it from there and do it declaratively on the actual properties that need that special format.

Such as:

[PropertyBinder(typeof(MyDecimalBinder))]
public decimal SomePropInAViewModel {get; set;}

This is based on a common approach of creating the PropertyBindingAttribute: http://www.prideparrot.com/blog/archive/2012/6/customizing_property_binding_through_attributes or https://stackoverflow.com/a/12683210/1373170

And with a ModelBinder similar to this:

public class MyDecimalBinder :  DefaultModelBinder {
    protected override void BindProperty(ControllerContext controllerContext, ModelBindingContext bindingContext, PropertyDescriptor propertyDescriptor) {

        // use the propertyDescriptor to make your modifications, by calling SetProperty()
        ...

        base.BindProperty(controllerContext, bindingContext, propertyDescriptor);
    }

}

Now, if this is something you want applied to ALL decimals, you might also want to check out Phil Haack's full implementation on handling decimals using a custom binder:

http://haacked.com/archive/2011/03/19/fixing-binding-to-decimals.aspx/

Upvotes: 1

user1968030
user1968030

Reputation:

See this article: 

public class HomeCustomDataBinder : DefaultModelBinder
{

    public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
    {
        if (bindingContext.ModelType == typeof(HomePageModels))
        {
            HttpRequestBase request = controllerContext.HttpContext.Request;

            string title = request.Form.Get("Title");
            string day = request.Form.Get("Day");
            string month = request.Form.Get("Month");
            string year = request.Form.Get("Year");

            return new HomePageModels
            {
                Title = title,
                Date = day + "/" + month + "/" + year
            };

            //// call the default model binder this new binding context
            //return base.BindModel(controllerContext, newBindingContext);
        }
        else
        {
            return base.BindModel(controllerContext, bindingContext);
        }
    }

}

Upvotes: 2

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