CODEWITHSUNDEEP
model-view-controllercakephplayout
Alex Ciminian
Alex Ciminian

Reputation: 11508

Dynamic layouts in CakePHP

Sorry about the question title, but I couldn't find a more appropriate way to phrase this.

I am currently building a CakePHP powered website and I'm not quite sure how to approach the following issue. The website looks something like the follwing mockup:

Website Mockup .

The greyed out areas are part of the layout, because their content does not change between views. In the sidebar, I have a collection of ads who are linked to several models. I need controller logic to determine the picture associated with an ad. Also, the ad list needs to be dynamic. Where should I put the logic for building the sidebar?

I've thought about:

What is the Cake way for this?

Update

After some reading and experimenting, I've gotten to refactoring most of it.

I obtained the best performance by moving the logic for building my ads in the model (eliminating the component that retrieved the pictures) and not using requestAction. It's almost three times faster and the code looks much better.

Upvotes: 4

Views: 3364

Answers (4)

Christopher Vrooman
Christopher Vrooman

Reputation: 31

Alex,

you're getting a SQL error because the build() function has to be in the Sidebar model, not controller. Also, you don't necessarily need to use $user = array('Sidebar'); you could calling Sidebar in all of your models with this:

$Sidebar = ClassRegistry::init('Sidebar'); and then $Sidebar->find();, $Sidebar->build(); etc.

Or, if you only need to call the build() function from the Sidebar model, you could do this: 

  $sidebar = ClassRegistry::init('Sidebar')->build();
  $this->set('sidebar', $sidebar);

Cheers.

Upvotes: 2

Mayank
Mayank

Reputation: 308

It can be done in this way:

  1. Create an element that will help in layout of the Ad Block
  2. Create one or more controller that will generate the data required for rendering of the block
  3. Use requestAction for getting the data out of the models and into the element.

Check the cake book, there is an example of an element where data from Post Model is used to display top/latest 5 posts. Your requirement, I feel, is very similar to it.

Upvotes: 2

harpax
harpax

Reputation: 6106

I guess the answer is requestAction in case the results are cachable:

http://book.cakephp.org/view/434/requestAction

Upvotes: 5

Rob Wilkerson
Rob Wilkerson

Reputation: 41236

I've done something similar for data-driven navigation. I put my logic in AppController::beforeRender and haven't had any problems. I'm not sure I understand your concern related to controller inheritance. I retrieve my menus via:

$menus = $this->NavMenuItem->groupByMenu();
$this->set( compact( 'menus' ) );

I then created an element that renders the menu. It's executed by the layout via:

<?php echo $this->element( 'navigation', array( 'id' => 'secondary', 'menu' => $menus['SECONDARY'] ) ) ?>

If that doesn't help, maybe you can further explain your issue with controller inheritance in a comment.

Upvotes: 5

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