Reputation: 1391
$resultSystem = mysql_query("SELECT * FROM templates where templateId = 1");
while($row = mysql_fetch_assoc($resultSystem))
{
$Part1 = $row["Part1"];
}
$name = "Peter";
echo $Part1;
In my database $Part1 results in $name. I would like the code to print the name "Peter", however it prints $name. How do I make PHP print the value of the variable?
Upvotes: 0
Views: 56
Reputation: 2802
if $Part1 = 'name';
$name ="Peter";
Then
echo $$Part1 will print "Peter"
Upvotes: 2
Reputation: 8578
Use function eval()
like
eval("echo $Part1");
However, be very careful so the users don't launch malicious code.
Upvotes: 0