CODEWITHSUNDEEP
javascriptjson
Stephenmelb
Stephenmelb

Reputation: 457

JSON Form.append

What is wrong with my code?

var form = $('#actor-form');

      form.append('<input name ="actor-id" type="hidden" value="' + datum.id + '">');
      form.append('<input name ="actor-email" type="hidden" value="' + datum.email + '">');
     })

})( jQuery );

It keeps throwing errors, should it be???

var form = $('#actor-form');

      form.append('<input name ="actor-id" type="hidden" value="' + datum.id + '">
                   <input name ="actor-email" type="hidden" value="' + datum.email + '">');
     })

})( jQuery );

I'm not sure. Please help!

Upvotes: 0

Views: 97

Answers (2)

user3309101
user3309101

Reputation: 26

If type is hidden then you can't test. i changed type as text to see if it is working or not. has to check your datum object also once for sure.

$(function(){
    var form = $('#actor-form');

    var datum = {};
        datum.id = 1001;
        datum.email = "[email protected]";

    form.append('<input name="actor-id" type="text" value="' + datum.id + '">');
    form.append('<input name="actor-email" type="text" value="' + datum.email + '">');
});

Upvotes: 1

maximkou
maximkou

Reputation: 5332

(function($) {
    // here initialize datum variable 
    var form = $('#actor-form');
    form.append('<input name ="actor-id" type="hidden" value="' + datum.id + '">');
    form.append('<input name ="actor-email" type="hidden" value="' + datum.email + '">');
})( jQuery );

Upvotes: 0

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