CODEWITHSUNDEEP
cwindowsfor-loopcodeblocksnested-loops
Phoenikzz
Phoenikzz

Reputation: 1

I need help on finishing my nested for loop in C to produce a specific output

I am trying to write a nested for loop in order to produce the following output:

 01234
  2345
   456
    67
     8

The code I have so far is:

#include <stdio.h>
#define SIZE 9

int main()
{
   int i, j;

   for(i=0; i < SIZE; i++)
   {
      for(j=0; j < SIZE; j++)
      {
         if(i <= j)
         {
            printf("%d", j);
         }
         else
         {
            printf(" ");
         }
      }
      printf("\n");
   }

   return 0;
}
/* This produces:
 * 012345678
 *  12345678
 *   2345678
 *    345678
 *     45678
 *      5678
 *       678
 *        78
 *         8
/*

Any help in the right direction would be appreciated, thanks!

Upvotes: 0

Views: 120

Answers (3)

BLUEPIXY
BLUEPIXY

Reputation: 40145

for(i=0; i < SIZE/2 + 1; i++){
    for(j=0;j<i+SIZE/2 + 1;++j)
        if(j<i*2){
            printf(" ");
            ++j;
        } else
            printf("%d", j);
    printf("\n");
}

Upvotes: 0

Lee Duhem
Lee Duhem

Reputation: 15121

Not a direct answer to the original question, but a solution to the task in the question:

#include <stdio.h>
#define LEVEL 5

int
main(void)
{
    int i, j;
    for (i = 0; i < LEVEL; i++) {
        for (j = 0; j < i; j++)
            printf(" ");
        for (j = i*2; j < LEVEL+i; j++)
            printf("%d", j);
        printf("\n");
    }
    return 0;
}

Upvotes: 0

doptimusprime
doptimusprime

Reputation: 9413

Try this.

int start,stop, k;
start = 0;
stop = SIZE/2 + SIZE%2;

while(start<=stop)
{
  for(k=0; k<start;++k)
      printf(" ");
  for(k=start;k<stop; ++k)
      printf("%d ", k);
printf("\n");

start+=2;
stop++;
}

printf("\n");

Analyze that common pattern is that start is increasing by 2 and stop is incremented by 1. Loop will over when start overtakes stop.

Upvotes: 1

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