Reputation: 127
I have an xml as below:
<root>
<book>abcd</book>
<pen>ghi</pen>
<source Qual="poor" vise="n">
<source>
<input value="in"></input>
<input></input>
</source>
</source>
<class>ab</class>
<source>noaatributes</source>
<studio>ghi</studio>
<source Qual="good" vise="m">
<source>
<input></input>
<input value="out"></input>
</source>
</source>
</root>
I would like to convert the xml in the below format :
<?xml version="1.0" encoding="utf-8" ?>
<root>
<book>abcd</book>
<pen>ghi</pen>
<poor value="in"/>
<class>ab</class>
<source>noaatributes</source>
<studio>ghi</studio>
<good value="out"/>
</root>
but the code i have written is not giving the required output..I have got stuck in middle of my coding..Any suggestions pls. Here is the code i have written so far :
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@* | node()">
<xsl:apply-templates select="@* | node()" />
</xsl:template>
<xsl:template match="source/@Qual">
<xsl:text disable-output-escaping="yes" ><![CDATA[
<]]></xsl:text>
<xsl:value-of disable-output-escaping="yes" select="."/>
</xsl:template>
<xsl:template match="source/source">
<xsl:apply-templates select="input"/>
<xsl:text disable-output-escaping="yes" ><![CDATA[
/>]]></xsl:text>
</xsl:template>
<xsl:template match="input">
<xsl:if test ="string-length(./@value) > 0">
<xsl:text disable-output-escaping="yes" ><![CDATA[
]]></xsl:text>
<xsl:text disable-output-escaping="yes" ><![CDATA[Value="]]></xsl:text>
<xsl:value-of disable-output-escaping="yes" select="./@value"/>
<xsl:text disable-output-escaping="yes" ><![CDATA[" ]]></xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Upvotes: 0
Views: 63
Reputation: 5432
This is going to be little smaller
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="root/source[@Qual]">
<xsl:element name="{@Qual[1]}">
<xsl:copy-of select="source/input/@value[1]"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Upvotes: 1
Reputation: 23637
To obtain the output you want, it can be much simpler:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(source[@Qual])]">
<xsl:copy-of select="."/>
</xsl:template>
<xsl:template match="source[@Qual]">
<xsl:element name="{@Qual}">
<xsl:attribute name="value">
<xsl:value-of select="source/input/@value" />
</xsl:attribute>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Upvotes: 0