CODEWITHSUNDEEP
pythonpandasfor-loopmatplotlibpandas-groupby
user3302483
user3302483

Reputation: 855

Pandas for loop on a group by

I have a dataset which has a category field, 'City' and 2 metrics, Age and Weight. I want to plot a scatterplot for each City using a loop. However I'm struggling to combine the group by and loop that I need in a single statement. If I just use a for loop I end up with a chart for each record and if I do a group by I get the right number of charts but with no values.

Here is my code using just the for loop with my group by commented out:

import pandas as pd
import numpy as np
import matplotlib.pylab as plt


d = {  'City': pd.Series(['London','New York', 'New York', 'London', 'Paris',
                        'Paris','New York', 'New York', 'London','Paris']),
       'Age' : pd.Series([36., 42., 6., 66., 38.,18.,22.,43.,34.,54]),
     'Weight': pd.Series([225,454,345,355,234,198,400, 256,323,310])
}

df = pd.DataFrame(d)

#for C in df.groupby('City'):
for C in df.City:
    fig = plt.figure(figsize=(5, 4))
    # Create an Axes object.
    ax = fig.add_subplot(1,1,1) # one row, one column, first plot
    # Plot the data.
    ax.scatter(df.Age,df.Weight, df.City == C, color="red", marker="^")

Upvotes: 3

Views: 8857

Answers (2)

unutbu
unutbu

Reputation: 879351

Do not call plt.figure more than once, as each call creates a new figure (roughly speaking, window).

import pandas as pd
import numpy as np
import matplotlib.pylab as plt

d = {'City': ['London', 'New York', 'New York', 'London', 'Paris',
                        'Paris', 'New York', 'New York', 'London', 'Paris'],
     'Age': [36., 42., 6., 66., 38., 18., 22., 43., 34., 54],
     'Weight': [225, 454, 345, 355, 234, 198, 400, 256, 323, 310]}

df = pd.DataFrame(d)
fig, ax = plt.subplots(figsize=(5, 4))    # 1
df.groupby(['City']).plot(kind='scatter', x='Age', y='Weight', 
                          ax=ax,          # 2
                          color=['red', 'blue', 'green'])

plt.show()

enter image description here

  1. plt.subplots returns a figure, fig and an axes, ax.
  2. If you pass ax=ax to Panda's plot method, then all the plots will show up on the same axis.

To make a separate figure for each city:

import pandas as pd
import numpy as np
import matplotlib.pylab as plt

d = {'City': ['London', 'New York', 'New York', 'London', 'Paris',
                        'Paris', 'New York', 'New York', 'London', 'Paris'],
     'Age': [36., 42., 6., 66., 38., 18., 22., 43., 34., 54],
     'Weight': [225, 454, 345, 355, 234, 198, 400, 256, 323, 310]}

df = pd.DataFrame(d)
groups = df.groupby(['City'])
for city, grp in groups:                           # 1
    fig, ax = plt.subplots(figsize=(5, 4))
    grp.plot(kind='scatter', x='Age', y='Weight',  # 2
             ax=ax)               

    plt.show()
  1. This is perhaps all you were missing. When you iterate over a GroupBy object, it returns a 2-tuple: the groupby key and the sub-DataFrame.
  2. Use grp, the sub-DataFrame instead of df inside the for-loop.

Upvotes: 2

user3302483
user3302483

Reputation: 855

I've used the group by from the other post and inserted into my code to generate a chart for each group by:

import pandas as pd
import numpy as np
import matplotlib.pylab as plt


d = {  'City': pd.Series(['London','New York', 'New York', 'London','Paris',
                        'Paris','New York', 'New York', 'London','Paris']),
       'Age' : pd.Series([36., 42., 6., 66., 38.,18.,22.,43.,34.,54]) ,
     'Weight': pd.Series([225,454,345,355,234,198,400, 256,323,310])

}

df = pd.DataFrame(d)

groups = df.groupby(['City'])
for city, grp in groups: 
    fig = plt.figure(figsize=(5, 4))
    # Create an Axes object.
    ax = fig.add_subplot(1,1,1) # one row, one column, first plot
    # Plot the data.
    ax.scatter(df.Age,df.Weight, df.City == city, color="red", marker="^")

Upvotes: 2

Related Questions