CODEWITHSUNDEEP
file-iolua
user3313535
user3313535

Reputation: 25

Passing file arguments to script in Lua

I need to read a input file which name I do not know.

I know that in C we can do this:

FILE *Ifile;
File *Ofile;

int main(int argc, char *argv[]){

    // Input and Output files
    Ifile = fopen(argv[1],"r");
    Ofile = fopen(argv[2],"w");

  (More code)
}

and then call "./cprogram <any file name>.txt <any file name>.txt"

Can I do something like this with .Lua scripts?

Upvotes: 1

Views: 1897

Answers (1)

user142162
user142162

Reputation:

Yes, you can. From the documentation:

Before starting to run the script, lua collects all arguments in the command line in a global table called arg. The script name is stored at index 0, the first argument after the script name goes to index 1, and so on.

For example, you could do the following:

if #arg < 2 then
    print ("usage: lua " .. arg[0] .. " <ifile> <ofile>")
    return
end

local ifile = io.open(arg[1], "r")
local ofile = io.open(arg[2], "w")
if not ifile or not ofile then
    print ("Error: could not open files")
    return
end

Upvotes: 4

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