CODEWITHSUNDEEP
cpointersarraysstruct
Pieter
Pieter

Reputation: 32805

Error working with structs and pointer arrays: incompatible types in assignment

#define STRMAX 50

struct Person {
    char sName[STRMAX];
    int iAge;
};
typedef struct Person PERSON;

int main() {
    PERSON *personen[1];
    personen[0]->sName = "Pieter";
    personen[0]->iAge = 18;

    return 0;
}

This code generates an error on personen[0]->sName = "Pieter"; saying incompatible types in assignment. Why?

Upvotes: 0

Views: 1425

Answers (4)

Toymakerii
Toymakerii

Reputation: 1540

I agree with the above but I figured it was also important to include the "why"

int a;      // is an integer
int *b;     // pointer to an integer must be malloced (to have an array)
int c[];    // pointer to an integer must also be malloced (to have an array)
int d[5];   // pointer to an integer bu now it is initialized to an array of integers

to get b and c from simple pointers and give them memory to match d use the following to give them memory space

b = (int *) malloc(sizeof(int)*5);

where it casts the pointer returned from malloc to an int pointer, and creates a memory block of 5 times the size of an integer (thus it will hold 5 integers like d)

Upvotes: 0

batbrat
batbrat

Reputation: 5231

You don't want an array of pointers. Try
PERSON personen[1];

And like others have said, use the strcpy function!

Upvotes: 2

codaddict
codaddict

Reputation: 455440

Change

PERSON *personen[1];

to

PERSON personen[1];

and use strcpy to copy the string.

strcpy(personen[0]->sName,"Pieter");

Upvotes: 1

user231967
user231967

Reputation: 1975

Don't try to assign arrays. Use strcpy to copy the string from one array to the other.

...sName is an array of chars while "Pieter" is a const char*. You cannot assign the latter to the former. The compiler is always right :)

Upvotes: 1

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