CODEWITHSUNDEEP
pythonintcallable
liamdiprose
liamdiprose

Reputation: 433

'int' Object not Callable

Im making a simple python script to process a table. I am using a array to store the cell values. Heres the code:

table =[]
hlen = input("Please enter the amount of columns \n")
vlen = input("Please enter the amount of rows \n")
curcol = 1
currow = 1
totcell = hlen*vlen
while (totcell >= curcol * currow):
   str = input("Please input "+ str(curcol) +"," + str(currow))
   table.append(str)
   if (curcol >= hlen):
       currow =+ 1

//Process Table

The program runs sweet, asking for the first cell at 1,1. All is well, until the code stops when reloading. Heres pythons error output

Traceback (most recent call last):
  File "./Evacuation.py", line 13, in <module>
    str = input("Please input "+ str(curcol) +"," + str(currow))
TypeError: 'int' object is not callable

Thanks for any help.

Upvotes: 0

Views: 166

Answers (3)

Benjamin
Benjamin

Reputation: 2286

  m = input("Please input "+ str(curcol) +"," + str(currow))
  please use different name of variable not use 'str' because it is python default function for type  casting

  table =[]
  hlen = input("Please enter the amount of columns \n")
  vlen = input("Please enter the amount of rows \n")
  curcol = 1
  currow = 1
  totcell = hlen*vlen
  while (totcell >= curcol * currow):
       m = input("Please input "+ str(curcol) +"," + str(currow))
  table.append(m)
  if (curcol >= hlen):
    currow += 1



   Please enter the amount of columns 
   5
  Please enter the amount of rows 
   1
  Please input 1,11
  Please input 1,11
  Please input 1,1
  >>> ================================ RESTART ================================
  >>> 
  >>>Please enter the amount of columns 
  >>>1
  Please enter the amount of rows 
  1
 Please input 1,12


 see this program and run it .

Upvotes: 1

mcw
mcw

Reputation: 545

You are using str as a variable name for the int you are returning from the input. Python is referring to that when you use str(curcol) and str(currow), rather than the Python string function.

Upvotes: 0

mhlester
mhlester

Reputation: 23251

You're shadowing the built in str with your variable name:

str = input("Please input "+ str(curcol) +"," + str(currow))

The second time around, with str(currow) you're trying to call str, which is now an int

Name it anything but that!

Also, you're in Python 2, so it's far preferred to use raw_input instead of input

Upvotes: 2

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