CODEWITHSUNDEEP
jsonrestgroovymockingsoapui
VRTHT
VRTHT

Reputation: 73

Mock Rest-Service Response (json and xml), using soapui

I'm getting a confused, because I'm beginner in mocking rest-services.

I'm using soapui to mock a rest-service. To do so, I need to write a script (OnRequest Script) in order to mock the responses to my request.

So, I want to mock 2 types of response : application/json and application/xml. But I don't want to read any response-file. I just want to write the response in the script (OnRequest Script, in soapui).

I've found a way to do it by reading a response file. In my case i don't need to read any file, rather write the response into the script (OnRequest Script, in soapui).

Some say that I can use groovy like this:

if (mockRequest.getMethod() == "GET" && mediaType=="application/xml"){
mockRunner.returnFile(httpResponse,new File(path + "test.xml"))
    log.info "Response returning for Content-Type application/xml"
    return new com.eviware.soapui.impl.wsdl.mock.WsdlMockResult(mockRequest)    
}

But the example does read a file, I want to use groovy but only writing the answer in groovy script.

Upvotes: 1

Views: 6453

Answers (1)

VRTHT
VRTHT

Reputation: 73

i've finally found how to fix that :

if (mockRequest.getMethod() == "GET" && mediaType=="application/xml"){
    WsdlMockResult mockResult = new WsdlMockResult(mockRequest)
    def httpResponse = mockRequest.httpResponse
    httpResponse.setContentType("application/xml;charset=utf-8")
    httpResponse.writer << "<root><user>ABC</user></root>"
    httpResponse.status = 200
    return mockResult
}

Enjoy this solution, if you need it.

Upvotes: 4

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