CODEWITHSUNDEEP
c#assembliesbuild-processrelease-modedebug-mode
born to hula
born to hula

Reputation: 1286

How to check if an assembly was built using Debug or Release configuration?

I'm starting deployment of my web application and I need to guarantee that all the assemblies that are going to be deployed were built using Release configuration. Our system was developed using C#/.Net 3.5.

Is there any way to achieve this?

Upvotes: 53

Views: 29690

Answers (6)

David
David

Reputation: 3609

Check this. The idea is that you get the list of assembly attributes using Assembly.GetCustomAttributes() and search for DebuggableAttribute and then find if such attribute has IsJITTrackingEnabled property set.

    public bool IsAssemblyDebugBuild(Assembly assembly)
    {
        return assembly.GetCustomAttributes(false).OfType<DebuggableAttribute>().Any(da => da.IsJITTrackingEnabled);
    }

Upvotes: 50

TrueWill
TrueWill

Reputation: 25563

Don't deploy to production via Visual Studio. Look into Continuous Integration and scripted builds (such as with NAnt, or perhaps something more legible like FAKE).

The F5 Key Is Not a Build Process

To detractors who believe that this does not answer the question, the OP wrote:

...I need to guarantee that all the assemblies that are going to be deployed were built using Release configuration.

To guarantee that, use a build server such as TeamCity and possibly a release management tool like Octopus Deploy. Lock down your production systems so that developers must go through the official build process.

Upvotes: 0

Guillermo Ruffino
Guillermo Ruffino

Reputation: 3020

If it is your assembly I believe using the AssemblyConfiguration attribute is the best approach. It is documented as "Specifies the build configuration, such as retail or debug, for an assembly."

Depending on your build configurations you might have code like this:

#if DEBUG
[assembly: AssemblyConfiguration("Debug")]
#else
[assembly: AssemblyConfiguration("Release")]
#endif

Then check the assembly attribute:

public static bool IsAssemblyConfiguration(Assembly assembly, string configuration)
{
    var attributes = assembly.GetCustomAttributes(typeof(AssemblyConfigurationAttribute), false);
    if (attributes.Length == 1)
    {
        var assemblyConfiguration = attributes[0] as AssemblyConfigurationAttribute;
        if (assemblyConfiguration != null)
        {
            return assemblyConfiguration.Configuration.Equals(configuration, StringComparison.InvariantCultureIgnoreCase);
        }
    }
    return true;
}

(I know R. Schreurs comment at Rubens Farias says the same, but I've find this information somewhere else before seeing the comment so I believe this requires a more important entry like a full response instead of a comment)

Upvotes: 11

Chris Voon
Chris Voon

Reputation: 1999

Assuming only Debug and Release configuration, DEBUG symbol is by default defined with Debug configuration, so the code below in AssemblyInfo.cs (under Properties folder).

#if DEBUG
[assembly: AssemblyTitle("Debug")]
#else
[assembly: AssemblyTitle("Release")]
#endif

I use AssemblyTitle over AssemblyDescription as it will show up on my Windows 7 file explorer properties:

DLL File properties

For those who like David and stevieg's answer, here is a LINQPad script written in C#. To use the script, you need to download LINQPad 5 and make sure C# Program is selected as shown in screenshot below.

Simply replace DLL_FOLDER_PATH to point to folder containing the DLLs to be inspected.

// TODO - Specify your folder containing DLLs to inspect
static string DLL_FOLDER_PATH = @"C:\Program Files (x86)\Reference Assemblies\Microsoft\Framework\.NETFramework\v4.0";
void Main()
{
    (from dllPath in Directory.GetFiles(DLL_FOLDER_PATH, "*.dll")
    let assembly = dllPath.SafeLoad()
    let build = assembly == null ? "Error" : (dllPath.SafeLoad().IsAssemblyDebugBuild() ? "Debug" : "Release")
    select new {
        Assembly_Path = dllPath,
        Build = build,
    }).Dump();
}
static class Extensions {
    public static bool IsAssemblyDebugBuild(this Assembly assembly)
    {
        return assembly.GetCustomAttributes(false).OfType<DebuggableAttribute>().Select(da => da.IsJITTrackingEnabled).FirstOrDefault();
    }
    public static Assembly SafeLoad(this string path){
        try{
            return Assembly.LoadFrom(path);
        }
        catch {
            return null;
        }
    }
}

Checking release or debug build using LINQPad5

LINQPAD 5 can be downloaded here.

Upvotes: 2

xr280xr
xr280xr

Reputation: 13302

If you have Reflector installed you can also click on the assembly and look for the debuggable attribute ([assembly: Debuggable()]) in the Disassembler pane.

Upvotes: 2

Rubens Farias
Rubens Farias

Reputation: 57996

I loved that David suggestion, but you could also go this way (AssemblyInfo.cs):

#if DEBUG
[assembly: AssemblyDescription("Your application assembly (DEBUG version)")]
#else if RELEASE
[assembly: AssemblyDescription("Your application assembly (RELEASE version)")]
#endif

This is more human friendly, as anyone can right-click that assembly, to select Properties and go to Details tab.

Upvotes: 30

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