tmighty
tmighty

Reputation: 11409

VB.NET: Load form and hide it

I have a form in my project. This form is only there to signalize to other application (for example external ActiveX-exes) that my application is still alive.

I have declared it like this in the main form:

Private m_fVirtualContainer As frmVirtualContainer

Now when I instantiate it, I say:

    m_fVirtualContainer = New frmVirtualContainer

However, this does not trigger the form's "Load" event.

I have to add m_fVirtualContainer.Show()

... to trigger the Load event.

In the form I have the following sub:

Private Sub frmVirtualContainer_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load

    Me.Visible = False

End Sub

But I think and hope that this is an overkill. I only want to load the form, not show it.

Can somebody please tell me how to do that? Thank you!

Upvotes: 0

Views: 9114

Answers (1)

jhayton
jhayton

Reputation: 315

Add a new module to project, this will act as the startup object for the project.

Sub Main()
' Instantiate a new instance of Form1.
Dim f1 as New Form1()
' Display a messagebox. This shows the application is running, 
' yet there is nothing shown to the user. This is the point at 
' which you customize your form.
System.Windows.Forms.MessageBox.Show("The application is running now, but no forms have been shown.")
' Customize the form.
f1.Text = "Running Form"
' Show the instance of the form modally.
f1.ShowDialog()
End Sub

Upvotes: 1

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