CODEWITHSUNDEEP
javaxpath
user3325651
user3325651

Reputation: 3

xpath not work correctly

XPATH : //requestHeader//*[local-name()='clientUsername']

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
  xmlns:req="http://www.ABC.com/ws/requestHeader"
  xmlns:web="http://com/ABC/XXX/YYY">
  <soapenv:Header/>
  <soapenv:Body>
    <web:isServiceUp>
      <web:requestHeader>
        <req:clientUsername>GENT</req:clientUsername>
        <req:languageCode>?</req:languageCode>
      </web:requestHeader>
    </web:isServiceUp>
  </soapenv:Body>
</soapenv:Envelope>

It suppose to be return GENT but It returns empty string...

Upvotes: 0

Views: 52

Answers (3)

Ian Roberts
Ian Roberts

Reputation: 122364

The requestHeader element is in the http://com/ABC/XXX/YYY namespace, so //requestHeader will not find it (that XPath is looking for an element named requestHeader in no namespace). You either need to do the same local-name() trick you're doing with clientUsername or set up the appropriate prefix binding using whatever mechanism your XPath library provides, and then use that prefix in the expression.

You've tagged your question "java" so if you're using javax.xml.xpath you need to look up the setNamespaceContext method on XPath.

Upvotes: 1

Vivin Paliath
Vivin Paliath

Reputation: 95488

You need to have the following:

//web:requestHeader//*[local-name()='clientUsername']

You need to look for web:requestHeader and not just requestHeader:

You can test this out here. Try it with just requestHeader and you'll see that it returns nothing. When you change it to web:requestHeader, you will get the element that you're looking for.

Upvotes: 2

Koitoer
Koitoer

Reputation: 19533

Try this one.

//web:requestHeader/req:clientUsername

Upvotes: 2

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