CODEWITHSUNDEEP
c++loopsfor-loopoperators
Moojave
Moojave

Reputation: 37

Addition and subtraction using increment and decrement operators. C++

I have been given a task to add and subtract two int variables WITHOUT using the built in operators (+ and -) and instead using the increment and decrement operators. How do I go about doing this?

    int add1;
    int add2; 
    int total;

    cout << "Please enter the 2 numbers you wish to add" << endl;
    cin >> add1;
    cin >> add2;

    //perform addition using increment operators

    return 0;

thanks for the help!

Upvotes: 0

Views: 3642

Answers (3)

Element808
Element808

Reputation: 1308

You have to use some sort of built in operators to perform this unless you are required to write a token parser and create your own interpreter and compiler. But I'm guessing since the question is quite basic, it's not asking you to do that.

You can simply do this:

int add1;
int add2;
cout << "Please enter the 2 numbers you wish to add" << endl;
cin >> add1;
cin >> add2;

//perform addition using increment operator
cout << (add1 += add2);

return 0;

EDIT - added decrement operator with less than or equal to 0 if/else:

int add1;
int add2;
int sub1;
int sub2;

cout << "Please enter the 2 numbers you wish to add" << endl;
cin >> add1;
cin >> add2;

//perform addition using increment operator
cout << (add1 += add2);

cout << "Please enter the 2 numbers you wish to subtract" << endl;
cin >> sub1;
cin >> sub2;

if((sub1 - sub2) <= 0)
{
    cout << "Number is less than or equal to 0." << endl;
}
else
    cout << (sub1 -= sub2);


return 0;

Upvotes: -1

Vlad from Moscow
Vlad from Moscow

Reputation: 310950

It is obvious that you need to use either loops or recursive functions. For example

int add1;
int add2;
cout << "Please enter the 2 numbers you wish to add" << endl;
cin >> add1;
cin >> add2;

int sum = add1; 
for ( int i = 0; i < add2; i++ ) ++sum;

int diff = add1; 
for ( int i = 0; i < add2; i++ ) --diff;

std::cout << "sum is equal to: " << sum << std::endl;  
std::cout << "difference is equal to: " << diff << std::endl;  

return 0;

Upvotes: 2

Ed Heal
Ed Heal

Reputation: 59997

Use a for loop.

e.g.

 for (; add1; add1--, add2++);

add2 will be add1 + add2 assuming add1 is positive

Similar idea for subtraction

Upvotes: 4

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