CODEWITHSUNDEEP
ccharacter-encodingchar
cp100
cp100

Reputation: 1493

Get binary content of char variable in C as it is

Is there a way to print binary content of char variable as it is. Means not to convert the variable in to ASCII.

For example,

char c =  1000001;
printf("%c\n", c);

This print

A

But I want to display without convert it to ascii something like below one.

1000001

Is that possible ?

Upvotes: 0

Views: 313

Answers (2)

user596031
user596031

Reputation: 26

can try looping.

scan your character,say 'A'. Get its ASCII(65). Divide 65 by 2 till quotient is zero, store remainder in array/dynmalloc . read the array reverse

65/2 32 1 32/2 16 0 16/2 8 0 8/2 4 0 4/2 2 0 2/2 1 0 1/2 0 1

Upvotes: 1

Jayesh Bhoi
Jayesh Bhoi

Reputation: 25885

you can do it by as follows

A char in C is guaranteed to be 1 byte, so loop to 8. Within each iteration, mask off the highest order bit. Once you have it, just print it to standard output.

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

int main(int argc,char *argv[]) 
{
      char c =  1000001;
      int i;
      for (i = 0; i < 8; i++) {
          printf("%d", !!((c << i) & 0x80));
      }
      printf("\n");

      return 0;


 }

or you can also use itoa library function as follows

char c = 'C'
char output[9];
itoa(c, output, 2);
printf("%s\n", output);

One more solution also

char c = 'C';
int i = 0;
    for (i = 7; i >= 0; --i)
    {
        putchar( (c & (1 << i)) ? '1' : '0' );
    }
    putchar('\n');

Upvotes: 1

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