CODEWITHSUNDEEP
javaunit-testingmockito
froi
froi

Reputation: 7788

Mockito verify order / sequence of method calls

Is there a way to verify if a methodOne is called before methodTwo in Mockito?

public class ServiceClassA {
    public void methodOne(){}
 }

public class ServiceClassB {
    public void methodTwo(){}
 }

public class TestClass {
    public void method(){
        ServiceClassA serviceA = new ServiceClassA();
        ServiceClassB serviceB = new ServiceClassB();
        serviceA.methodOne();
        serviceB.methodTwo();
    }
}

Upvotes: 300

Views: 180502

Answers (6)

Valerij Dobler
Valerij Dobler

Reputation: 2804

When verifying the invocation order of a single method call with different arguments it's essentially the same:

ServiceClass myMock = mock(ServiceClassA.class);

InOrder inOrder = inOrder(myMock);

inOrder.when(myMock).myMethod(42);
inOrder.when(myMock).myMethod(69);

Upvotes: 0

user3193413
user3193413

Reputation: 654

For Kotlin users, you can go this way:

class MyTrackerTest {
    private val trackEventUseCase: TrackEventUseCase = mock()
    private val sut = MyTracker(trackEventUseCase)

    @Test
    fun `trackSomething SHOULD invoke tracker use case twice with correct event names WHEN called`() {
        sut.trackSomething()

        trackEventUseCase.inOrder {
            verify().invoke("Is it August?")
            verify().invoke("No!")
        }
    }

}

Upvotes: 7

Thracian
Thracian

Reputation: 67463

With BDD it's

@Test
public void testOrderWithBDD() {


    // Given
    ServiceClassA firstMock = mock(ServiceClassA.class);
    ServiceClassB secondMock = mock(ServiceClassB.class);

    //create inOrder object passing any mocks that need to be verified in order
    InOrder inOrder = inOrder(firstMock, secondMock);

    willDoNothing().given(firstMock).methodOne();
    willDoNothing().given(secondMock).methodTwo();

    // When
    firstMock.methodOne();
    secondMock.methodTwo();

    // Then
    then(firstMock).should(inOrder).methodOne();
    then(secondMock).should(inOrder).methodTwo();


}

Upvotes: 2

Jon Thoms
Jon Thoms

Reputation: 10797

Note that you can also use the InOrder class to verify that various methods are called in order on a single mock, not just on two or more mocks.

Suppose I have two classes Foo and Bar:

public class Foo {
  public void first() {}
  public void second() {}
}

public class Bar {
  public void firstThenSecond(Foo foo) {
    foo.first();
    foo.second();
  }
}

I can then add a test class to test that Bar's firstThenSecond() method actually calls first(), then second(), and not second(), then first(). See the following test code:

public class BarTest {
  @Test
  public void testFirstThenSecond() {
    Bar bar = new Bar();
    Foo mockFoo = Mockito.mock(Foo.class);
    bar.firstThenSecond(mockFoo);

    InOrder orderVerifier = Mockito.inOrder(mockFoo);
    // These lines will PASS
    orderVerifier.verify(mockFoo).first();
    orderVerifier.verify(mockFoo).second();

    // These lines will FAIL
    // orderVerifier.verify(mockFoo).second();
    // orderVerifier.verify(mockFoo).first();
  }
}

Upvotes: 147

LaurentG
LaurentG

Reputation: 11827

Yes, this is described in the documentation. You have to use the InOrder class.

Example (assuming two mocks already created):

InOrder inOrder = inOrder(serviceAMock, serviceBMock);

inOrder.verify(serviceAMock).methodOne();
inOrder.verify(serviceBMock).methodTwo();

Upvotes: 45

Koitoer
Koitoer

Reputation: 19543

InOrder helps you to do that.

ServiceClassA firstMock = mock(ServiceClassA.class);
ServiceClassB secondMock = mock(ServiceClassB.class);

Mockito.doNothing().when(firstMock).methodOne();   
Mockito.doNothing().when(secondMock).methodTwo();  

//create inOrder object passing any mocks that need to be verified in order
InOrder inOrder = inOrder(firstMock, secondMock);

//following will make sure that firstMock was called before secondMock
inOrder.verify(firstMock).methodOne();
inOrder.verify(secondMock).methodTwo();

Upvotes: 445

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