CODEWITHSUNDEEP
python
AndroidDev
AndroidDev

Reputation: 21237

Python - reference a file in a different directory

I have to reference a file that exists in a different directory. This is just a text file, not a python module. I've read countless posts, most of which are about including modules. Nothing that I read is giving me a successful answer. Out of many attempts, this is my latest:

import os
REMOTE_FILE = open(os.path.join('/Users/me/Dropbox/otherfolder', 'text.txt'), "r")
decrypted = subprocess.check_output(['openssl', 'aes-128-cbc', '-d', '-in', REMOTE_FILE, '-base64', '-pass', key])

The program doesn't fail on this line immediately, but when I attempt to reference this file I get:

TypeError: Can't convert '_io.TextIOWrapper' object to str implicitly

What am I doing wrong? Thanks!

Upvotes: 1

Views: 2166

Answers (2)

Josh Durham
Josh Durham

Reputation: 1662

Use REMOTE_FILE = os.path.join('/Users/me/Dropbox/otherfolder', 'text.txt') instead to get only the file path as a string and not an file object.

Upvotes: 2

AlG
AlG

Reputation: 15157

Your REMOTE_FILE is a file object, not a string. Given your code, you probably meant to do:

import os
REMOTE_FILE = os.path.join('/Users/me/Dropbox/otherfolder', 'text.txt')
decrypted = subprocess.check_output(['openssl', 'aes-128-cbc', '-d', '-in', REMOTE_FILE, '-base64', '-pass', key])

Keeping REMOTE_FILE as a string, not an object.

Upvotes: 1

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