CODEWITHSUNDEEP
c#xml
user3331487
user3331487

Reputation: 43

change value of XML element

I have XML which is in project folder. I am loading the contents using this

    XmlDocument doc = new XmlDocument();
    string testFilesLocation = System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location);
    string dataSource;
    string xmlFileName = "Claim.txt";

    if (System.IO.Directory.Exists(testFilesLocation + @"\Resources"))
    {
        dataSource = testFilesLocation + @"\Resources\" + xmlFileName;
    }
    else
    {
        dataSource = testFilesLocation + @"\" + xmlFileName;
    }
    doc.Load(dataSource);

XML has following nodes 

<ClaimKeyInfo>
    <CompanyID>XXXX</CompanyID>
    <ClaimNum>XX-XXXXX-XX<ClaimNum>
</ClaimKeyInfo>   

<ClaimInfo>
    <ClaimNum>XX-XXXXX-XX</ClaimNum>
    <ClaimSensitivityInd>N</ClaimSensitivityInd>
    <ClaimStatus>Open</ClaimStatus>
<ClaimInfo>

I am doing this to get ClaimNum elements 

    XmlElement root = doc.DocumentElement;
    XmlNodeList elemList = root.GetElementsByTagName("ClaimNum");
    for (int i = 0; i< elemList.Count; i++)
    {
        elemList[i].InnerXml = "YY-YYYYY-YY";
        doc.Save(dataSource);
    }

I do get both the elements in elemList but I am not able to change the values inside it.

Any help would be appreciated.

Upvotes: 0

Views: 74

Answers (1)

Selman Gen&#231;
Selman Gen&#231;

Reputation: 101701

You can use LINQ to XML for that.

var xDoc = XDocument.Load("filePath");
var numbers = xDoc.Descendants("ClaimNum");

foreach(var number in numbers)
{
    // do your work with numbers
    number.Value = "123456";
}

xDoc.Save("filePath");

Here, the numbers are contains XElements which is your ClaimNums.You can change the Value property and save the XML file.If you want to get specific numbers you can use Where extension method.If you want more details see these documentations:

Upvotes: 1

Related Questions