CODEWITHSUNDEEP
phparrays
Swapnil
Swapnil

Reputation: 51

How print array value which stored in another array

$res stores result query and function output.

When I write

print_r($res);

then output is :

Array ( [0] => Array ( [@out] => 50 [0] => 112 ) )

Now, I want to print values 112 and 50.
And I want to store that value in another variable.

Upvotes: 0

Views: 68

Answers (5)

TURTLE
TURTLE

Reputation: 3847

Access the array values by keys like the following.

/* Your array */
$res = array(
   "0" => array(
      "@out" => "50",
      "0" => "112"
   )
);

/* Returns 50 */
echo $res['0']['@out'];

/* Returns 112 */
echo $res['0']['0'];

Upvotes: 0

Mr. Bhosale
Mr. Bhosale

Reputation: 3106

You use ..

1st [0] is the index number and '@out' is ID .

That type of result got only on stored procedures...

$val = $res[0]['@out']; $val2 = $res[0]['0'];

echo $val; // to print value 50

echo $val2; // to print value 112

Upvotes: 0

krishna
krishna

Reputation: 4089

Your array is multidimensional array.so for storing values in to another variable and if you know the keys of the array use this

$value1 = $res[0]['@out'];
$value2 = $res[0]['0'];

to print try this

echo $value1;

echo $value2;

Upvotes: 0

Ravinder Reddy
Ravinder Reddy

Reputation: 24002

Try: 

/* To store in other variables */  
$out_value = $res[ 0 ][ '@out' ];  
$zero_indexed_value = $res[ 0 ][ '0' ];  

/* To print */  
print_r( $out_value );  
print_r( $zero_indexed_value );

Upvotes: 0

GautamD31
GautamD31

Reputation: 28753

Simple

echo $res[0]['@out'];
echo $res[0]['0'];

Upvotes: 2

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