Reputation: 43
I have a table of items available for purchases which I am displaying on the site. I am using mysql to fetch all the items and display them in a table. Among others, the table contains this:
<input type="hidden" name="price" id="price'.$id.'"> //id is one part of MySQL query results
<input type="text" name="count_'.$id.'">
All this is displayed for around 200 items with ID being not completely in sequence (I found some JavaScript code that used for (i = 0; i < rows.length; i++) {}
, however, with my IDs not being in a sequence, this is not a good option for me).
I would like to display a total of an order using JavaScript and I am not experienced when it comes to JS. I would be very thankful for your advices.
Upvotes: 1
Views: 780
Reputation: 16103
I suggest you wrap them in another element, lets use div
. Add a class to that, lets say moneyline
<div class="moneyline">
<input class="price" type="hidden" name="price" id="price'.$id.'"> //id is one part of MySQL query results
<input class="quantity" type="text" name="count_'.$id.'">
</div>
Im going to give the example with jQuery, and some button to trigger it:
$('#someButton').on('click', function(){
var total = 0;
$('.moneyline').each(function(){
var price = parseInt($(this).find('.price'), 10);
var quantity = parseInt($(this).find('.quantity'), 10);
total+= quantity*price;
});
alert( total );
});
Upvotes: 0
Reputation: 1
Consider adding a class to each element that you want to count and see the answer below on stackoverflow. You should be able to have a counter for each occurrence of the class and show this variable in the html
How to getElementByClass instead of GetElementById with Javascript?
<div class="item"> ... <your inputs> ... </div>
Upvotes: 0
Reputation: 4397
You coul duse jQuery
:
function orderTotal()
{
var total=0;
$('input[name="price"]').each(function(){
var price = parseFloat($(this).val());
var amount = parseFloat($('input[name="count_'+$(this).attr('name').substring(5)+'"]').val());
total += price+amount;
});
return total;
}
Upvotes: 1