CODEWITHSUNDEEP
pythonrandominteger
ArjunLotay
ArjunLotay

Reputation: 119

Repeated Random Numbers

I have created a bingo game where random numbers are generated and called for a list. 

bingo_num = random.randint(1,100)

How would I stop a random number being generated more than once

Upvotes: 3

Views: 319

Answers (7)

Ian Ellis
Ian Ellis

Reputation: 389

Build list of all the numbers then select a random 1, remove it from the list then select the next one:

#!/usr/bin/python
import random

myNumz=[]
xIdx=1
while xIdx<101:
myNumz.insert(xIdx,xIdx)
    xIdx+=1

xIdx=100
while xIdx>0:
    xIdx-=1
    baseNum=random.randint(0,xIdx)
    print myNumz[baseNum]
    myNumz.remove(myNumz[baseNum])

Upvotes: 0

Claus
Claus

Reputation: 150

You could first create a list containing all possible numbers. Then pick a random number from that list, add that to a result list and finally remove it from the list of possible numbers.

For example if you want 5 different numbers from 0-9:

possible_numbers = range(10)
numbers = []

for i in range(5):
    index = random.randint(0, len(possible_numbers) - 1)
    numbers.append(possible_numbers[index])
    del possible_numbers[index]

Upvotes: 1

tobias_k
tobias_k

Reputation: 82899

Just do it the same way they do it in a real Bingo game. They do not roll dices, but put all the numbers in a big bag, shake it, and pull out numbers one at a time, until all the numbers are used up.

numbers = list(range(1, 101)) # all the numbers in the bag, from 1 to 100
random.shuffle(numbers)       # shake the bag
bingo_num = numbers.pop()     # pull out next number (inside your loop)

Upvotes: 2

Kuishi
Kuishi

Reputation: 157

You could just create a new number if already in use

advantage: easy code

disadvantage: will run long if nearly all numbers are use (there are better solutions)

Sample code:

bingo_num_list = []

# init num
bingo_num = random.randint(1,100)

# create new numbers till "find" a not used one
while bingo_num in bingo_num_list:
    bingo_num = random.randint(1,100)

bingo_num_list.append(bingo_num)

Upvotes: 0

markcial
markcial

Reputation: 9323

You can take a sample of a range from the random library

>>> import random
>>> nums = random.sample(range(0,200),100)
>>> nums
[143, 149, 52, 183, 161, 179, 180, 155, 163, 157, 139, 15, 154, 181, 56, 29, 31,
 14, 77, 82, 165, 32, 35, 92, 109, 172, 69, 99, 54, 3, 88, 76, 11, 126, 78, 162,
 198, 145, 124, 75, 114, 174, 136, 100, 190, 193, 148, 153, 167, 113, 38, 17, 16
8, 0, 196, 73, 47, 164, 184, 6, 140, 30, 58, 74, 4, 79, 147, 178, 191, 21, 112,
13, 27, 57, 199, 116, 28, 104, 111, 71, 23, 85, 170, 25, 141, 156, 91, 7, 182, 1
34, 94, 169, 175, 166, 137, 160, 129, 36, 67, 135]

Upvotes: 3

sheepez
sheepez

Reputation: 1012

Something like this should work:

numbers = []
while len(numbers) < 100:
    bingo_num = random.randint(1,100)

    if not bingo_num in numbers:
        numbers.append(bing_num)

Upvotes: 0

thefourtheye
thefourtheye

Reputation: 239443

I would suggest, random.shuffle

from random import shuffle
my_list = range(100)
shuffle(my_list)
print my_list

But if you need only specific amount of unique numbers, you can use random.sample, like this

from random import sample
my_list = range(100)
print sample(my_list, 10)

Upvotes: 3

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