CODEWITHSUNDEEP
javascriptjqueryjsonobject
user1162328
user1162328

Reputation:

Filtering results of JSON Object

var employees = {
"staff": [
  {"name": "Bob", "gender": "Male"},
  {"name": "Sue", "gender": "Female"},
  {"name": "Eric", "gender": "Male"},
  {"name": "Jo", "gender": "Female"}    
  ]
}

After iterating through this json structure, is there a method to selectively delete an entire row based on the gender selection? Ideally I'd like to have a new object but without any Males, for example.

Upvotes: 2

Views: 182

Answers (3)

Tom
Tom

Reputation: 7740

employees.staff = filter(employees.staff, "Female");

function filter(data, filter) {
    return data.filter(function(row) {
        return row.gender === filter;
    });
}

Upvotes: 0

Arun P Johny
Arun P Johny

Reputation: 388316

use $.grep() - Array.filter() is not used because of IE < 9 support

var females = $.grep(employees.staff, function (obj) {
    console.log(this, arguments)
    return obj.gender == "Female"
})
console.log(females)

Another solution is to use Array.filter() with the pollyfill

Upvotes: 2

Pointy
Pointy

Reputation: 413702

There's the .filter() function:

employees.staff = employees.staff.filter(function(e) { return e.gender !== "Male"; });

The .filter() method is available for arrays in newer versions of JavaScript (modern browsers). For older browsers, there is a polyfill available.

Upvotes: 5

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