CODEWITHSUNDEEP
awk
junda
junda

Reputation: 51

How to print regex expression in awk?

I have a file with hundreds of lines with contents that looks like this:

6281316
6281315
6281317

I simply want to use awk to transform them into regex expression so I could use it later.

/6281316/
/6281315/
/6281317/

howerver, when I run:

awk '{print "/"$1"/"}' file.txt

it give back

/6281316
/6281315
/6281317

Does anybody could point out where I went wrong?

Thank you very much

Upvotes: 1

Views: 74

Answers (2)

jaypal singh
jaypal singh

Reputation: 77085

There is nothing wrong with your command. Your file has windows formatting. Convert the file to unix format using dos2unix and re-run the command.

Upvotes: 3

Ell
Ell

Reputation: 947

Your command works for me without any issue. Maybe try a sed solution:

sed 's/^/\//;s/$/\//' file.txt

Upvotes: 0

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