CODEWITHSUNDEEP
bashgrep
Johnbritto
Johnbritto

Reputation: 149

How to grep a exact word from a variable contains sentence

I have tried upto my knowledge to get the result but i couldn't. I request you to guide me in a correct way.

Bellow is my bash script which is actually an init.d script.

#!/bin/bash

LOG_LEVEL="info debug_rpc warn test critical debug_sql error debug debug_rpc_answer notset"
CHECK_LOG_LEVEL=$2

logcheck() {
if [ ! -z $CHECK_LOG_LEVEL ]; then
    if [ "$(grep -o "$LOG_LEVEL")" == "$CHECK_LOG_LEVEL" ]; then
       echo "Starting the daemon with log_level"
    else
        echo "Check if the log-level argument name is correct!"
    exit 1
    fi
else
    echo "Starting the daemon"
fi
}

case "${1}" in
        start)
                logcheck
                ;;
        esac

exit 0

I want the grep to match the exact word. because of debug_rpc, debug_rpc_answer, debug_sql

if you user make a typo mistake by running script as: sudo /etc/init.d/myscript.sh start debug_rp

it need to display {echo "Check if the log-level argument name is correct!"}

I am trying to match exact user argument stored in variable $CHECK_LOG_LEVE with content $LOG_LEVEL

Any guidance or workaround for this..

Thanks.

Upvotes: 1

Views: 1282

Answers (2)

glenn jackman
glenn jackman

Reputation: 247210

LOG_LEVEL="info debug_rpc warn test critical debug_sql error debug debug_rpc_answer notset"
CHECK_LOG_LEVEL=$2

# spaces below are very deliberate
if [[ " $LOG_LEVEL " != *" $CHECK_LOG_LEVEL "* ]]; then
    echo "invalid log level" >&2
    exit 1
fi

"debug_rp" will not pass that check, but "info debug_rpc" will, if someone is determined to provide invalid input

for exact matching, use an array:

LOG_LEVEL=( info debug_rpc warn test critical debug_sql error debug debug_rpc_answer notset )
CHECK_LOG_LEVEL=$2

found=false
for lvl in "${LOG_LEVEL[@]}"; do
    if [[ $CHECK_LOG_LEVEL == $lvl ]]; then
        found=true
        break
    fi
done
if ! $found; then
    echo "invalid log level" >&2
    exit 1
fi

Upvotes: 2

anubhava
anubhava

Reputation: 786091

You can use this grep -qw (match word):

if grep -qw "$CHECK_LOG_LEVEL" <<< "$LOG_LEVEL"; then
    echo "valid log-level argument"
else
    echo "Check if the log-level argument name is correct!"
fi

Afterwards you can check return status using $?

Upvotes: 2

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