CODEWITHSUNDEEP
c#wpfxaml
Mikasuki
Mikasuki

Reputation: 35

Select a combo box item XAML

Im trying to do a CASE for the option quality but Im receiving a operator error of "==" what is the solution for this problem.?

This is the code behind 

  private void myComboBoxThatICreatedInXaml_SelectionChanged(object sender, SelectionChangedEventArgs e)
    {

        if (myComboBoxThatICreatedInXaml.SelectedValue.ToString == Low)
        {
            QualityChoices.Add(YouTubeQuality.QualityHigh);

            case
                (myComboBoxThatICreatedInXaml.SelectedValue.ToString == Medium)
            {
                QualityChoices.Add(YouTubeQuality.QualityMedium);
            }
            case
               (myComboBoxThatICreatedInXaml.SelectedValue.ToString == High)
            {
                QualityChoices.Add(YouTubeQuality.QualityHigh);
            }

        }

And this is my xaml code.

   <ComboBox x:Name="myComboBoxThatICreatedInXaml" SelectionChanged="myComboBoxThatICreatedInXaml_SelectionChanged" >
            <ComboBoxItem Tag="LW">Low</ComboBoxItem>
            <ComboBoxItem Tag="MD">Medium</ComboBoxItem>
            <ComboBoxItem Tag="HG">High</ComboBoxItem>
        </ComboBox>

Upvotes: 0

Views: 213

Answers (1)

McGarnagle
McGarnagle

Reputation: 102723

You've got some C# syntax problems going there. You need () for the ToString method, and quote-marks around the string literals:

if (myComboBoxThatICreatedInXaml.SelectedValue.ToString() == "Low")

If you wanted to use a switch statement, then it's like this:

switch(myComboBoxThatICreatedInXaml.SelectedValue.ToString())
{
    case "Low":
        QualityChoices.Add(YouTubeQuality.QualityHigh);
        break;
    case "Medium":
        QualityChoices.Add(YouTubeQuality.QualityMedium);
        break;
    case "High":
        QualityChoices.Add(YouTubeQuality.QualityHigh);
        break;
    default:
        break;
}

Upvotes: 3

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