Reputation: 317
I am trying to figure out how to remove all unique rows, from a data frame, but if it has a duplicate, I want that to stay in. For Example - I want all columns from this with col1 the same:
df<-data.frame(col1=c(rep("a",3),"b","c",rep("d",3)),col2=c("A","B","C",rep("A",3),"B","C"),col3=c(3,3,1,4,4,3,2,1))
df
col1 col2 col3
1 a A 3
2 a B 3
3 a C 1
4 b A 4
5 c A 4
6 d A 3
7 d B 2
8 d C 1
subset(df,duplicated(col1))
col1 col2 col3
2 a B 3
3 a C 1
7 d B 2
8 d C 1
But I want to have rows 1,2,3,6,7,8 since they all have the same col 1. How do I get 1 and 6 to be included? Or, conversely, how do I remove rows that do not have a duplicate?
Upvotes: 9
Views: 9025
Reputation: 52637
You can do this by creating an index with ave
:
df[as.logical(ave(1:nrow(df), df$col1, FUN=function(x) length(x) > 1)), ]
produces
col1 col2 col3
1 a A 3
2 a B 3
3 a C 1
6 d A 3
7 d B 2
8 d C 1
Upvotes: 3
Reputation: 44614
Another option:
subset(df,duplicated(col1) | duplicated(col1, fromLast=TRUE))
Upvotes: 18
Reputation: 2785
Try:
> tdf <- table(df$col1)
a b c d
3 1 1 3
df[df$col1 %in% names(tdf)[tdf>1],]
> df
col1 col2 col3
1 a A 3
2 a B 3
3 a C 1
6 d A 3
7 d B 2
8 d C 1
Upvotes: 6