CODEWITHSUNDEEP
c++regex
user3341779
user3341779

Reputation: 39

C++ regex: split the string

I am trying to search and split a string based on regex. Suppose I have a string named var which looks like 

|   | | |-DeclRefExpr 0x5d91218 <col:5> 'int' lvalue Var 0x5d91120 'y' 'int'

Now I would like to split this into 

|   | | |-DeclRefExpr 0x5d91218 <col:5> 
int
 lvalue Var 0x5d91120 
y

int

I know that the regex will be something like [^']* but I cant figure out how I can do it. What I have tried so far is:

#include <string.h>
#include <stdlib.h>
#include <iostream>
#include <regex>

using namespace std;

int main(){

    std::string var = "    |   | | |-DeclRefExpr 0x5d91218 <col:5> 'int' lvalue Var 0x5d91120 'y' 'int'";

    std::regex rgx("[^']*");
    std::smatch match;
    if (std::regex_search(var.begin(), var.end(), match, rgx)){
        cout << match[3] << endl;
    }
    return 0;
}

Upvotes: 0

Views: 3183

Answers (2)

herohuyongtao
herohuyongtao

Reputation: 50717

Besides @CasimiretHippolyte's method, you can also use regex_search():

const regex r("(.*)'(.*)'(.*)'(.*)'(.*)'(.*)'");  
smatch sm;

if (regex_search(var, sm, r))
{
    for (int i=1; i<sm.size(); i++)
    {
        cout << sm[i] << endl;
    }
}

See it live: http://coliru.stacked-crooked.com/a/494ab2e0f1c5d420

Upvotes: 0

Casimir et Hippolyte
Casimir et Hippolyte

Reputation: 89639

Sorry I can't test this code, but it can perhaps work.

std::string var = "|   | | |-DeclRefExpr 0x5d91218 <col:5> 'int' lvalue Var 0x5d91120 'y' 'int'";
std::regex wsaq_re("\\s*'|'+\\s*(?!')"); 
std::copy( std::sregex_token_iterator(var.begin(), var.end(), wsaq_re, -1),
    std::sregex_token_iterator(),
    std::ostream_iterator<std::string>(std::cout, "\n"));

Upvotes: 3

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