CODEWITHSUNDEEP
javathymeleaf
Tom
Tom

Reputation: 17864

thymeleaf - combined th:each with th:href

I'm new to Thymeleaf (and webdev) and I'm trying to combine Thymeleaf iteration (th:each) with URL re-writing (th:href).

<a th:each="lid : ${lists}" th:text="${lid}" th:href="@{/list?l=${lid}}">
hello
</a>

This produces the following (where lid=45):

<a href="/list?l=${lid}">45</a>

So, it did the substitution on the th:text, but not on the th:href.

I'm not trying to do any sort of URL re-writing, I'm just using the '@' syntax because I want Thymeleaf to substitute the 'lid' attribute.

I'm using the current version of Thymeleaf (2.1.2) with Google App Engine.

Upvotes: 5

Views: 13221

Answers (3)

Tom Verelst
Tom Verelst

Reputation: 15992

If you don't want to do any url rewriting, you shouldn't use the @ syntax.

You can use the pipeline (|) syntax to do some literal substitions:

th:href="|/list?l=${lid}|"

Source: Thymeleaf documentation

Upvotes: 7

C. Springer
C. Springer

Reputation: 193

I don't have enough reputation to add a comment on a previous post but the Thymeleaf Source documentation link from a previous post is broken. Documentation can now be found at the following link:

Thymeleaf Standard URL Syntax

Section 9 Using Expressions in URLs in this documentation explains how you can use expressions within other expressions when generating URLs with the @ syntax. The following is an example:

<a th:href="@{/order/details(id=${modelattribute})}"/>

Will produce a link similar to:

http://domain.org/context/order/details?id=1

if modelattribute had a value of 1 in the current context.

Upvotes: 2

Iwo Kucharski
Iwo Kucharski

Reputation: 3825

You can also try this way:

<a th:href="@{'/list?l=' + ${lid}}" th:text="${lid}">element</a>

Upvotes: 4

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