CODEWITHSUNDEEP
javamethodsprogram-entry-point
abc
abc

Reputation: 315

calling main method inside main in java

Can we call main method inside main?

public static void main(String[] args) {
    main({"a","b","c"});
}

Tried to google.Can't find the link. Sorry if the question is trivial

Upvotes: 4

Views: 27001

Answers (5)

Anshuman Singh
Anshuman Singh

Reputation: 1

You can simply pass the argument like main(new String[1]) - this line will call main method of your program. But if you pass "new String[-1]" this will give NegativeArraySizeException. Here I'mm giving an example of Nested Inner Class where I am calling the Main method:

class Outer 
{
    static class NestedInner
    {

        public static void main(String[] args)
        {
            System.out.println("inside main method of Nested class");

        }//inner main
    }//NestedInner
    public static void main(String[] args) 
    {

        NestedInner.main(new String[1] );//**calling of Main method**
        System.out.println("Hello World!");
    }//outer main
}//Outer

Output:- inside main method of Nested class

Hello World!

Upvotes: 0

John Red
John Red

Reputation: 717

You can. And it is very much legal.
Also, it doesn't necessarily give a StackOverFlowError: 

public static void main(String args[]){

    int randomNum = (int)(Math.random()*10);

    if(randomNum >= 8)
    System.exit(0);

    System.out.print("Heyhey!");
    main(new String[]{"Anakin", "Ahsoka", "Obi-Wan"});

}

Just saying.

Upvotes: 5

Sarah
Sarah

Reputation: 525

Kugathasan is right.

Yes it does give StackOverflow Exception. I tested it right now in Eclipse. 

class CallingMain
{
    public static void main(String[] args)
    {
         main(new String[] {"a","b","c"});
    }
}

I have one suggestion, I think the best way to eliminate the confusion is to try coding and running it. Helps with lots of doubts.

Upvotes: 1

Reimeus
Reimeus

Reputation: 159874

You can but using the correct format

main(new String[] {"a","b","c"});

should give StackOverFlowError (not tested)

Upvotes: 17

Abimaran Kugathasan
Abimaran Kugathasan

Reputation: 32498

You will get StackOverFlowError. If you call endless recursive calls/deep function recursions.

Thrown when a stack overflow occurs because an application recurses too deeply.

You need to pass String array like

main(new String[] {"a","b","c"});

Upvotes: 4

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