Reputation: 1981
I have a jquery modal that is being called from a button on my page. When the Webmethod for this button is called, and all logic is complete, I need to refresh several update panels on my page, to reflect the changes that took place in the WebMethod.
I've not used Update Panel much, but i've followed a view examples and am drawing a blank.
In the success portion of my call, i've placed this:
success: function (msg) {
$('#ApproveDialog').modal('hide');
__doPostBack("<%= UpdatePanel1 %>","");
and my update panel is:
<asp:Button ID="button" runat="server" style="display:none;"/>
<asp:UpdatePanel runat="server" ID="UpdatePanel1" UpdateMode="Conditional">
<ContentTemplate>
<asp:GridView ID="grdMessageDate" runat="server"/> </ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="button" EventName="Click"/>
</Triggers>
</asp:UpdatePanel>
I've left out part of the Grid, but i have a button in the first col, which is used to display further information.
When i click the button in the grid. this is causing the postback.
How do i call the postback in the success method?
Upvotes: 0
Views: 56
Reputation: 2460
You should be able to postback in the success like so:
__doPostBack("UpdatePanel1","");
or if the updatepanel gets an asp.net formated id:
__doPostBack("<%= UpdatePanel1.ClientID %>","");
Otherwise you could use the hidden button technique (I use this, but don't think it is the most elegant method)
see post: Force a postback in Javascript for UpdatePanel?
Upvotes: 1