Reputation: 31
Here is my version of the code right now and I keep getting list index error.
n = 0
y = len(list1)-1
while n < y:
for k in list1:
if list1[n]+ k == g:
print("The 2 prime numbers that add up to ",g,"are ", list1[n]," and ",k,".")
break
else:
n = n+1
Upvotes: 0
Views: 175
Reputation: 1
You left a few bits of information out, but I gather that you are trying to find 2 primes that match a target. In order to access a list in this manner, you need to enumerate it.
y = len(list1) - 1
while n < y:
for n, k in enumerate(list1):
if list1[n]+ k == g :
print("The 2 prime numbers that add up to ",g,"are ", list1[n]," and ",k,".")
break
However, you don't really need the index, two for loops would accomplish the same thing.
target = 8
primes = [2, 3, 5, 7, 11, 13, 17, 19]
message = 'The 2 prime numbers that add up to {target} are {value1} and {value2}'
for index1, value1 in enumerate(primes):
for value2 in primes[index1 + 1:]:
if value1 + value2 == target:
print(message.format(target=target, value1=value1, value2=value2))
Upvotes: 0
Reputation: 19641
You are incrementing n
in the for
loop but testing its contraint in the outer while
loop.
Perhaps this is what you wanted:
n = 0
y = len(list1)-1
found = 0
while n < y:
for k in list1:
if list1[n]+ k == g:
print("The 2 prime numbers that add up to ",g,"are ", list1[n]," and ",k,".")
found = 1
break # for loop
if found:
break # while loop
n = n + 1
A much better way to do it is using itertools.combinations_with_replacement
:
import itertools
for (v1,v2) in itertools.combinations_with_replacement(list1, 2):
if v1 + v2 == g:
print("blah blah blah")
break
combinations_with_replacement(list1,2)
will return all the unordered combinations of two elements of list1
. For instance, combinations_with_replacement('ABC', 2) --> AA AB AC BB BC CC
Upvotes: 2