CODEWITHSUNDEEP
phpjqueryhtmlsqlforms
user1033038
user1033038

Reputation: 141

Dynamic checkboxes not posted over form

I have a div element which will auto populate a list of checkboxes on changing a value from another drop down list. The checkboxes are populated fine, however the 'pl' parameter cannot be posted over to the other form, createreport.php on submitting the form.

Entry form:

 $.ajax({
     type: "POST",
     url: "loadData.php",
     data: dataString,
     cache: false,
     success: function(result){
       $("#loader").fadeOut(600);
       $("#inputpl").empty().append(result);
     }
   });

    <form action="createreport.php" method="post">
              <div class="form-dropdown" style="width:300px" id="inputpl" name="pl">

    //////////checkboxes populated here. If I hard code the checkboxes here, it can be passed over successfully

              </div>
    <input type="submit" />
    </form>

loadData.php:

for($i=0; $i<=odbc_fetch_row($result); $i++){
                $name = odbc_result($result, 1);


                echo '<input type="checkbox" name="pl[]" value="'.$name.'" />'.$name.'<br/>';
            }

createreport.php:

  echo '<pre>';
    print_r($_POST['pl']);
    echo '</pre>';

Output:

Notice: Undefined index: pl in C:\inetpub\wwwroot\test\createreport.php on line 21

EDIT: I am able to alert the value of the checkboxes by adding this to the submit button:

  $('input[type="checkbox"]:checked').each(function(){
        alert(this.value);
    })

Upvotes: 0

Views: 71

Answers (2)

Sarath
Sarath

Reputation: 608

I think you have submit the form without checking any checkboxes thats why the error is reported

please try following code

if(isset($_POST['pl'])){
echo '<pre>';
    print_r($_POST['pl']);
    echo '</pre>';
    }

Upvotes: 0

000
000

Reputation: 27247

for($i=0; $i<=odbc_fetch_row($result); $i++){
    $name = odbc_result($result, 1);
    echo '<input type="checkbox" name="pl[]" value="'.$name.'" />'.$name.'<br/>';
}

odbc_fetch_row returns a boolean for a successful fetch. You want this:

<?php
while (odbc_fetch_row($result)) {
    $name = odbc_result($result, 1);
    echo '<input type="checkbox" name="pl[]" value="'.$name.'" />'.$name.'<br/>';
}

It doesn't look like anything would have been returned from loadData.php anyway.

Upvotes: 1

Related Questions