CODEWITHSUNDEEP
phpcss
Priya jain
Priya jain

Reputation: 703

how to apply class according to the filename?

i have created an application where i want to apply active class on active page. Like if fike name starts with me_ then how can i apply class "active" to it.

here is my code:

$pageAttr       =   basename($_SERVER['REQUEST_URI']);  
$files          =   array("me_dashboard.php","me_my_team.php","me_others.php","me_inbox.php","me_outbox.php"); 


<li class="<?php echo($pageAttr == $files[0] || $pageAttr == $files[1] || $pageAttr == $files[2] || $pageAttr == $files[3] || $pageAttr == $files[4]) ? "active":"" ?>"><a href="me_dashboard.php"><i class="icon-user icon-large"></i> Me</a></li>

this is not correct code to use. Please suggest me some other ways to achieve the solution in PHP.

Upvotes: 0

Views: 71

Answers (2)

Mr. Alien
Mr. Alien

Reputation: 157384

If you have array of files like this

$files = array("me_dashboard.php",
                "me_my_team.php",
                "me_others.php",
                "me_inbox.php",
                "me_outbox.php"
          );

Than you can use in_array() like

<li class="<?php echo (in_array(basename($_SERVER['PHP_SELF']), $files) ? 'active' : '')?>">

It will be even better if you port the class= attribute in the if condition as well, so that you do not get an empty class="" markup.

If you want to refactor your code more, consider porting entire code in a function, and then return the value if condition goes true.

As commented, you wanted to fetch the prefix of the file than you can use substr()

<?php
    $page_name = 'me_dashboard.php';
    $fetch_prefix = substr($page_name, 0, 3);
    echo $fetch_prefix;
?>
<li class="<?php echo (($fetch_prefix == 'me_') ? 'active' : '')?>">A</li>

Demo - Code

Upvotes: 2

Satish Sharma
Satish Sharma

Reputation: 9635

you can try this one

<?php
$pageAttr       =   basename($_SERVER['REQUEST_URI']);  
$files          =   array("me_dashboard.php","me_my_team.php","me_others.php","me_inbox.php","me_outbox.php"); 

foreach($files as $file)
{
    $class_text = "";
    if($file==$pageAttr)
    {
        $class_text = ' class="active" ';
    }
    ?>
        <li <?php echo $class_text;?> ><a href="<?php echo $file;?>"><i class="icon-user icon-large"></i> Me</a></li>
    <?php
}
?>

Upvotes: 1

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