manish singh
manish singh

Reputation: 1453

Error: CUICatalog: Invalid asset name supplied: (null), or invalid scale factor : 2.000000

TableViewApplication[1458:70b] CUICatalog: Invalid asset name supplied: (null), or invalid scale factor: 2.000000

Screenshot added

Getting this warning while working with TableViewController. How to rectify this error and which block is affected?

Upvotes: 145

Views: 97383

Answers (13)

Naresh
Naresh

Reputation: 17892

In my case I have implemented cell with UILabel, UIImageView and UITextFied, sometimes I don't want to display image, in that case I'm sending empty string "" to the imageView. Now the same error/warning is getting.

Error: [framework] CUICatalog: Invalid asset name supplied: ''

Solution is we have to pass nil instead of "" empty string.

Code:

if imgName.count > 0 {
    selectedIconView.image = UIImage(named: imgName)
} else {
    selectedIconView.image = nil 
    //You can also use
    //selectedIconView.isHidden = true 
}

Upvotes: 0

idrougge
idrougge

Reputation: 721

This happened to me after a storyboard was split into several (the actual change happened when I was on holidays, so I don't know exactly how it was done).

After inspecting the XML of the storyboards, I found that an image reference which previously had pointed to "bottomBar" in the assets catalogue instead pointed to imageView:fFo-1g-jzs:image.

At the end of the XML file under the <resources> tag was tag named <image name="imageView:fFo-1g-jzs:image"> containing a big mutableData blob.

After resetting the image reference in the storyboard and removing the blob, the error went away.

Upvotes: 3

tt.Kilew
tt.Kilew

Reputation: 6084

This one appears when someone is trying to put nil in [UIImage imageNamed:]

Add symbolic breakpoint for [UIImage imageNamed:]Symbolic breakpoint example

Add $arg3 == nil condition on Simulator, $r0 == nil condition on 32-bit iPhone, or $x2 == nil on 64-bit iPhone.

Run your application and see where debugger will stop.

P.S. Keep in mind this also happens if image name is empty string. You can check this by adding [(NSString*)$x2 length] == 0 to the condition.

Upvotes: 280

Tenma Tobyo
Tenma Tobyo

Reputation: 1

Maybe you can use this to confirm the "imageName" is not a "nil";Then you will leave away this warning.

 if (imageName) {
    self.imageView.image = [UIImage imageNamed:imageName];
 }

Upvotes: -1

Ash
Ash

Reputation: 5712

You are supplying some invalid image name, so need to validate before putting it you can do any of the above ways whichever make sense for your code or like

if (iconImageName && [iconImageName length])
{

    [UIImage imageNamed:iconImageName];
}
else
{
     iconImageName.hidden = YES;
}

Hope it will help!!!!

Upvotes: 2

Haoxin Li
Haoxin Li

Reputation: 81

One approach is do class method swizzling to replace [UIImage imageNamed:] with your own implementation, then check the image name in your implementation. See the following:

How to swizzle a class method on iOS?

I implemented this in my UIImage(Debug) category:

+ (UIImage *)db_imageNamed:(NSString *)imageName {
    if ([imageName length] == 0) {
        NSLog(@"breakpoint here");
    }
    return [self db_imageNamed:imageName];  // not a recursive call here after swizzling
}

You might want to swizzle [UIImage imageNamed:inBundle:compatibleWithTraitCollection:] as well.

Upvotes: 0

Meilbn
Meilbn

Reputation: 592

I got this warning when I load image use [[UIImage imageNamed:normalStr] imageWithRenderingMode:UIImageRenderingModeAlwaysOriginal], than, I change to [UIImage imageNamed:normalStr], warning was gone.

Upvotes: 0

Bharath
Bharath

Reputation: 324

The Reason to the error is passing a nil value to the "imageNamed:" method. To avoid this, you can hide your imageView when you try to pass the nil value. The chances may occur in reusing the imageViews in UITableView or may be in scrollViews.

I avoided the warning with the below check :

UIImageView *your_image_view;
NSString *imageName;
if(imageName && imageName.length){
 your_image_view.hidden = NO;
 your_image_view.image = [UIImage imageNamed:imageName];
}
else {
 your_image_view.hidden = YES;
}

Upvotes: 0

ginchly
ginchly

Reputation: 355

In Xcode 6.4, this seems to occur when using "Selected Image" for a tab bar item in the storyboard, even if it's a valid image.

enter image description here

This doesn't actually seem to set the selected state image anyway, so it needs to be defined in User Defined Runtime Attributes, and removed from the SelectedImage attribute of the Tab Bar Item

enter image description here

Upvotes: 16

Rahul Mathur
Rahul Mathur

Reputation: 882

In my case i was passing [UIImage imageNamed:@""] which caused me to show the warning. Just add breakpoints to all the lines where you have used imageNamed and the debug the line where you find the warning.

Upvotes: 5

passwind
passwind

Reputation: 149

I have just fixed this error. Just check the usage of the [UIImage imageNamed:(NSString*) imageName] function. If the imageName is nil, then error occurs.

Upvotes: 1

Fabio
Fabio

Reputation: 1855

This error (usually) happens when you try to load an image with [UIImage imageNamed:myImage] but iOS is not sure if myImage is really a NSString and then you have this warning.

You can fix this using:

[UIImage imageNamed:[NSString stringWithFormat:@"%@", myImage]]

Or you can simply check for the length of the name of the UIImage:

if (myImage && [myImage length]) {

    [UIImage imageNamed:myImage];
}

Upvotes: 68

robotspacer
robotspacer

Reputation: 2762

Since the error is complaining that the name you gave is (null), this is most likely caused by calling [UIImage imageNamed:nil]. Or more specifically, passing in a variable hasn't been set, so it's equal to nil. While using stringWithFormat: would get rid of the error, I think there's a good chance it's not actually doing what you want. If the name you supply is a nil value, then using stringWithFormat: would result in it looking for an image that is literally named "(null)", as if you were calling [UIImage imageNamed:@"(null)"].

Something like this is probably a better option:

if (name) {
    UIImage *image = [UIImage imageNamed:name];
} else {
    // Do something else
}

You might want to set a breakpoint in Xcode on that "Do something else" line, to help you figure out why this code is getting called with a nil value in the first place.

Upvotes: 22

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