CODEWITHSUNDEEP
javalucene
gozizibj
gozizibj

Reputation: 285

How to escape all Special Characters from whole string at one go in Java

Lucene supports escaping special characters that are part of the query syntax. The current list special characters are

+ - && || ! ( ) { } [ ] ^ " ~ * ? : \

To escape these character use the \ before the character. For example to search for (1+1):2 use the query:

\(1\+1\)\:2

My question is how to escape from whole string at one go? For example myStringToEscape = "ABC^ " ~ * ? :DEF"; How to get a escapedString.

Upvotes: 7

Views: 15150

Answers (2)

ADDruid
ADDruid

Reputation: 196

If you are just looking for simple replacement, this will do the trick.

String regex = "([+\\-!\\(\\){}\\[\\]^\"~*?:\\\\]|[&\\|]{2})";

String myStringToEscape = "ABC^ \" ~ * ? :DEF";
String myEscapedString = myStringToEscape.replaceAll(regex, "\\\\$1");

System.out.println(myEscapedString);

This will output:

ABC\^ \" \~ \* \? \:DEF

Upvotes: 4

femtoRgon
femtoRgon

Reputation: 33351

You can use QueryParser.escape, such as:

String escapedString = queryParser.escape(searchString);
queryParser.parse("field:" + escapedString);

Upvotes: 14

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