CODEWITHSUNDEEP
pythonsocketsrpyc
changzhi
changzhi

Reputation: 2709

Python rpyc "socket.error: [Errno 113] No route to host"

I have two machines using python rpyc ,one is server(ip:10.0.3.120), another is client(ip:10.0.3.197). The code shows below:

Server (ip:10.0.3.120)

from rpyc import Service
from rpyc.utils.server import ThreadedServer

class TestService(Service):

    def exposed_test(self, num):
        return num + 1

sr = ThreadedServer(TestService, port=9999, auto_register=False)
sr.start()

Client (ip:10.0.3.129)

import rpyc
conn = rpyc.connect('10.0.3.120', 9999)
cResult = conn.root.test(11)
conn.close()

print cResult

Client shows this error when I run server and client:

Traceback (most recent call last):
File "rpyc_client.py", line 4, in <module>
conn = rpyc.connect('10.0.3.120', 9999)
File "/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/utils/factory.py", line 89, in connect
s = SocketStream.connect(host, port, ipv6 = ipv6)
File "/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/core/stream.py", line 114, in connect
return cls(cls._connect(host, port, **kwargs))
File "/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/core/stream.py", line 92, in _connect
s.connect((host, port))
File "/usr/local/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)

How does connect method use? If I use public network IP to build a rpyc server, could I connect it at home ?? Thanks a lot!

Upvotes: 2

Views: 14129

Answers (2)

Ian
Ian

Reputation: 23

Just delete all iptables rules on the client with this command:

iptables -F

Upvotes: 1

Peter Kozhevnikov
Peter Kozhevnikov

Reputation: 143

First, check for a connection command ping. In your code server runs at localhost. In order so that it can be accessed from outside your correct address or * (then the server will run on all possible addresses of the current machine). I think auto_register must be equal to None.

from rpyc import Service
from rpyc.utils.server import ThreadedServer

class TestService(Service):

    def exposed_test(self, num):
        return num + 1

sr = ThreadedServer(TestService, hostname='10.0.3.120', port=9999, auto_register=None)
# or sr = ThreadedServer(TestService, hostname='*', port=9999, auto_register=None)
sr.start()

Upvotes: 1

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