CODEWITHSUNDEEP
if-statementprintingawk
Marwai
Marwai

Reputation: 11

condition on print in an awk if statment

I'm working on a little code with awk: I'm looking for a pattern and if its find I would like to print the newt 3 lines. Without an if, no problem:

awk '/\/1/ {x=NR+3}(NR<=x) {print > "out"}' input

the file I use:

@_5:1:7:9569:21200/1  
CAGAATGCCGTGGAACTGAAACGTCTGGC
+  
CCCFFFFFHHHHHJJJJIJJIHIJJIJJI
@_5:1:7:9569:21200/2
GCACCATCATCACCGGTTCCGGGCAGCGC
+  
CCCFFFFFHHFHHJJJGHJJJJJJJIGGI
@_5:1:11:12099:7543/1  
CAGAATGCCGTGGAACTGAAACGTCTGGC

I would like to separate this file in two others as follow

File 1
@_5:1:7:9569:21200/1  
CAGAATGCCGTGGAACTGAAACGTCTGGC
+  
CCCFFFFFHHHHHJJJJIJJIHIJJIJJI
@_5:1:11:12099:7543/1  
CAGAATGCCGTGGAACTGAAACGTCTGGC

File 2
 @_5:1:7:9569:21200/2
GCACCATCATCACCGGTTCCGGGCAGCGC
+  
CCCFFFFFHHFHHJJJGHJJJJJJJIGGI

But with the if I have syntax error on the print

awk '{ if (/\/1/) {x=NR+3}(NR<=x) {print > "file1"};} else (/\/2/) {x=NR+3}(NR<=x) {print > "file2"}' "input_file"

If someone has an idea to fix that

Thanks!

Upvotes: 1

Views: 522

Answers (1)

Jotne
Jotne

Reputation: 41446

Some like this:

awk -F"/" '/^@/ {f=$2} {print > ("file"f+0)}' data

Need to add the +0 to remove space after the line.

cat file1
@_5:1:7:9569:21200/1
CAGAATGCCGTGGAACTGAAACGTCTGGC
+
CCCFFFFFHHHHHJJJJIJJIHIJJIJJI
@_5:1:11:12099:7543/1
CAGAATGCCGTGGAACTGAAACGTCTGGC


cat file2
@_5:1:7:9569:21200/2
GCACCATCATCACCGGTTCCGGGCAGCGC
+
CCCFFFFFHHFHHJJJGHJJJJJJJIGGI

Using -F/ divide line into $1 and $2 by the separator /
{f=$2} store the last digit of line starting with @
Then data is written to "file"f" so when f=1, it would be file1 etc.

Upvotes: 1

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