CODEWITHSUNDEEP
androidandroid-layoutwidthandroid-view
AggieDev
AggieDev

Reputation: 5045

Making a View's width based on screen width

I am trying to let a View's width be based on the width of the screen. Depending on a value from 0 to 100, the width will be that percentage of the screen width. Here is how I am getting the screen width in DP:

Display display = ((Activity)context).getWindowManager().getDefaultDisplay();
DisplayMetrics outMetrics = new DisplayMetrics ();
display.getMetrics(outMetrics);
float density  = context.getResources().getDisplayMetrics().density;
float screenWidthDP = outMetrics.widthPixels / density;

This returns 360dp for my device which is correct. I then use this to set the width of my view, where timeCountNewRange() returns a value from 0 - 100:

int timeCountNewRange = getNewRangeTimeCount(timeCount, min, max);
int widthDP = (int) (((double)timeCountNewRange / 100.0) * screenWidthDP);

LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(widthDP, 15);
params.setMargins(5, 0, 0, 0);
appHolder.timeBar.setLayoutParams(params);

For some reason, when the "timeCountNewRange" value is 100 it is only about 60% of the screen width, and everything else is shorter as well. If replace

LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(widthDP, 15);

with 

LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(360, 15);

the view is still only around 60% of the screen width. This error differs from device to device based on screen size. How do I properly set the width to be based upon the screen width?

Upvotes: 5

Views: 1311

Answers (1)

arul
arul

Reputation: 300

The layout params will be set in pixels if set programmatically. You will have to convert the dp to pixels again and set the width

Upvotes: 2

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