Reputation: 1
I'm trying to create a linked list structure to store data. The head of the linked list seems to be updating somehow. I have the following code. I can't seem to figure out how put char array data into a node and keep it from updating when the address to said char array's data updates.
The following code prints out whatever string is passed into the processStr function. How do I keep head from updating ?
//Linked List Structure
mainNode *head = NULL;
//take and store word in data structure
void processStr(char *str){
//char array
char strArray[sizeof(str)+1];
//stores lower case string
char strLower[strlen(str)];
int i;
for(i = 0; str[i]; i++)
strLower[i] = tolower(str[i]);
strLower[i] = '\0';
//printf("%s : ", strLower);
//Starts Linked List
if(head == NULL){
mainNode *mainPtr = (mainNode *)malloc(sizeof(mainNode));
nameNode *namePtr = (nameNode *)malloc(sizeof(nameNode));
mainPtr->name = strLower;
mainPtr->numOccurances = 1;
mainPtr->next = NULL;
mainPtr->nextName = namePtr;
namePtr->name = strArray;
namePtr->next = NULL;
head = mainPtr;
}
printf("%s : " , head->name);
}
Upvotes: 0
Views: 153
Reputation: 7918
The above code will only run once only which will add information to head only once. If you want to add more information in case of second run then add code for else condition. Example:-
if ( head == NULL ) {
// code to insert data in case of first run
}else{
// code to insert data for second run and so.....
}
Upvotes: 0
Reputation: 9904
You assign the pointers mainPtr->name
and namePtr->name
to variables strLower
and strArray
that are declared locally in processStr()
. That means after that function returns, any access to these pointers results in undefined behaviour. You could do sth. like
mainPtr->name = strdup( strLower );
instead to allocate memory for the strings.
Btw.: strLower
must also be declared as char strLower[strlen(str)+1];
Upvotes: 1