CODEWITHSUNDEEP
phpregextext-extraction
Jakub Fedor
Jakub Fedor

Reputation: 275

Get text that follows a regex pattern match

I'm struggling to find out how I can get the text after a regex match (until the end of word).

Ex 1:
Input: my home
Regex: /hom/
Result: e

Ex 2:
Input: soulful
Regex: /soul/
Result: ful

Upvotes: 4

Views: 6550

Answers (4)

mickmackusa
mickmackusa

Reputation: 47874

If you only need the trailing text and not the fullstring match, then use \K to forget previously matched characetrs. This eliminates the need to use a character class and populate a second element in the matches array.

Code: (Demo)

var_dump(preg_match('/hom\K.+/', 'my home', $m) ? $m[0] : '');
// string(1) "e"

var_dump(preg_match('/soul\K.+/', 'soulful', $m) ? $m[0] : '');
// string(3) "ful"

If this is a sanitization task and you know that the substring will be found in the string, then you can use preg_replace() to match the front of the string. Demo

var_dump(preg_replace('/.*hom/', '', 'my home'));
// string(1) "e"

var_dump(preg_replace('/.*soul/', '', 'soulful'));
// string(3) "ful"

Upvotes: 1

ziollek
ziollek

Reputation: 1993

You can expand your regex to match all text after original regex, ie:

$string = 'soulful';
$regex = '/soul(.*)/';
if ( preg_match($regex, $string, $match) ) {
 echo 'The text after soul is: '.$match[1].PHP_EOL;
}

Upvotes: 1

elixenide
elixenide

Reputation: 44823

Just change your regex to use a group with ( and ):

$string = 'soulful';
$regex = '/soul(.+)/';
preg_match($regex, $string, $matches);
var_dump($matches);

Output:

array(2) {
    [0]=> string(7) "soulful"
    [1]=> string(3) "ful"
    }

Upvotes: 2

anubhava
anubhava

Reputation: 784998

You can use:

$str = 'soulful';
$reg = '/soul(\w+)/';
if ( preg_match($reg, $str, $m) )
   print_r ($m);

OUTPUT

Array
(
    [0] => soulful
    [1] => ful
)

Upvotes: 6

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