Reputation: 1279
I have a table with many(+1000) columns and rows(~1M). The columns have either the value 1 , or are NULL.
I want to be able to select, for a specific row (user) retrieve the column names that have a value of 1.
Since there are many columns on the table, specifying the columns would yield a extremely long query.
Upvotes: 0
Views: 1912
Reputation: 325141
You're doing something SQL is quite bad at - dynamic access to columns, or treating a row as a set. It'd be nice if this were easier, but it doesn't work well with SQL's typed nature and the concept of a relation. Working with your data set in its current form is going to be frustrating; consider storing an array, json
, or hstore
of values instead.
Actually, for this particular data model, you could probably use a bitfield. See bit(n)
and bit varying(n)
.
It's still possible to make a working query with your current model PostgreSQL extensions though.
Given sample:
CREATE TABLE blah (id serial primary key, a integer, b integer, c integer);
INSERT INTO blah(a,b,c) VALUES (NULL, NULL, 1), (1, NULL, 1), (NULL, NULL, NULL), (1, 1, 1);
I would unpivot each row into a key/value set using hstore
(or in newer PostgreSQL versions, the json functions). SQL its self provides no way to dynamically access columns, so we have to use an extension. So:
SELECT id, hs FROM blah, LATERAL hstore(blah) hs;
then extract the hstore
s to sets:
SELECT id, k, v FROM blah, LATERAL each(hstore(blah)) kv(k,v);
... at which point your can filter for values matching the criteria. Note that all columns have been converted to text
, so you may want to cast it back:
SELECT id, k FROM blah, LATERAL each(hstore(blah)) kv(k,v) WHERE v::integer = 1;
You also need to exclude id
from matching, so:
regress=> SELECT id, k FROM blah, LATERAL each(hstore(blah)) kv(k,v) WHERE v::integer = 1 AND
k <> 'id';
id | k
----+---
1 | c
2 | a
2 | c
4 | a
4 | b
4 | c
(6 rows)
Upvotes: 1