CODEWITHSUNDEEP
bashsh
James Wise
James Wise

Reputation: 1805

Carriage return \r on bash script

I have this bash script on my CentOS 5.3.

#!/bin/bash

RESULT=$(cat /tmp/logfile.log | grep -i "Backlog File Count" | awk '{print $6}')

if [ "${RESULT}" -lt "5" ];
  then
      echo "${RESULT} is less than 5"
  else
      echo "${RESULT} is greater than 5"
fi


/tmp/logfile.log:

Backlog File Names (first 1 files)

This bash script should supposedly to get the value "1" on the log file and print the output. However, when I run the script, this is the error message:

: integer expression expected

So when I set the debug mode, I found the "RESULT" variable output:

+ RESULT=$'1\r'
.....
+ '[' $'1\r' -lt 5 ']'

I've noticed that "\r" output is attached on the value.

I would appreciate if any one could lead me why there is "\r" on that output and how to get rid of that error. I tried on CentOS 6.3 and there is no issue.

# rpm -qa bash
bash-3.2-32.el5_9.1

Thank you. James

Upvotes: 1

Views: 12049

Answers (1)

devnull
devnull

Reputation: 123448

Your input file contains CR+LF line endings. Strip the CR before reading the variable. Say:

RESULT=$(tr -d '\r' < /tmp/logfile.log | grep -i "Backlog File Count" | awk '{print $6}')

Alternatively, you could remove the carriage returns from the input file by using dos2unix or any other utility.

Moreover, saying:

cat file | grep foobar

is equivalent to saying:

grep foobar file

and avoids the Useless Use of Cat.

Upvotes: 4

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