CODEWITHSUNDEEP
php
user1269625
user1269625

Reputation: 3209

PHP 5 code not working in PHP 4

I have this function in PHP 5:

function myPHPFunction($shows) {

        foreach($shows as &$show) {
                        $showData = $this->Api->getID(null, $show->showId, false);
                        $show->Id = $showData->Id;
        }
        return $shows;
}

the $shows array has empty id, I am able to get the id with an Api call and when I return $shows at the end, the id field is populated. If I move this code to PHP 4:

function myPHPFunction($shows) {

        foreach($shows as $show) {
                        $showData = $this->Api->getID(null, $show->showId, false);
                        $show->Id = $showData->Id;
        }
        return $shows;
}

The $shows array still has an empty id field when I return is. Does it have something to with &$ because the & does not work in PHP 4

Upvotes: 0

Views: 45

Answers (1)

Shankar Narayana Damodaran
Shankar Narayana Damodaran

Reputation: 68476

Yes pass by reference was available only after PHP 4.0.4

There is no reference sign on a function call - only on function definitions. Function definitions alone are enough to correctly pass the argument by reference. As of PHP 5.3.0, you will get a warning saying that "call-time pass-by-reference" is deprecated when you use & in foo(&$a);. And as of PHP 5.4.0, call-time pass-by-reference was removed, so using it will raise a fatal error.

Source

Upvotes: 1

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