Reputation: 627
How can I create an array based on certain conditions in another array. For example, if I have an array that gives me a Base number, a start and end number, and then multiple other Base numbers. I want to create a new matrix that lists the Base number, the loop number (based on start/end) and then the other Base number associated with this, while ignoring 0's. I am trying to find a way to do this without using a for loop.
For example, how can I get array B from array A.
Base Start End Base1 Base2 Base3
A=np.array([[100, 1, 2, 101, 102, 103],
[101, 3, 4, 100, 103, 0]])
B=np.array[[100,1,101,1],
[100,1,102,1],
[100,1,103,1],
[100,2,101,2],
[100,2,102,2],
[100,2,103,2],
[101,3,100,3],
[101,3,103,3],
[101,4,100,4],
[101,4,103,4]]
Thanks for the help!
Upvotes: 4
Views: 948
Reputation: 10769
Here you go: pure numpy, no for loops at the python level
C = np.empty((len(A), 2,3,4), np.int)
C[...,0] = A[:,0 ][:,None,None]
C[...,1] = A[:,1:3][:,: ,None]
C[...,2] = A[:,3: ][:,None,: ]
C[...,3] = np.arange(len(A)*2).reshape(len(A),2,1)+1
C = C.reshape(-1,4)
C = C[C[:,2]!=0]
print C
edit: minor cleanup
edit2: or for maximum brevity and crypticity (see comment):
C = np.empty((len(A), 2,3,2,2), np.int)
C[...,0,0] = A[:,0 ][:,None,None]
C[...,1,0] = A[:,3: ][:,None,: ]
C[...,:,1] = A[:,1:3][:,: ,None,None]
Upvotes: 2
Reputation: 2532
Here you go... nasty list comprehension
A = array([[100, 1, 2, 101, 102, 103], [101, 3, 4, 100, 103, 0]])
B = [[A[i,0], b, c, b] for i in range(len(A)) for b in A[i,1:3] for c in A[i,3:6] if c != 0]
>>> B
[[100, 1, 101, 1],
[100, 1, 102, 1],
[100, 1, 103, 1],
[100, 2, 101, 2],
[100, 2, 102, 2],
[100, 2, 103, 2],
[101, 3, 100, 3],
[101, 3, 103, 3],
[101, 4, 100, 4],
[101, 4, 103, 4]]
Upvotes: 2