CODEWITHSUNDEEP
pythondjangofilepostupload
ccamacho
ccamacho

Reputation: 739

Uploading files from a Python client to a Django Server

I'm trying to upload some files from a Python client to a Django web app.

I'm able to do it by using a form, but I don't know how to do it using a stand alone Python app. Can you give me some suggestions?

I'm modeling the files in a Django model like this:

class Media(models.Model):
    post = models.ForeignKey(Post)
    name = models.CharField(max_length=50, blank=False,null=False)
    mediafile = models.FileField(upload_to=media_file_name, blank=False,null=False)

Cheers.

Upvotes: 1

Views: 2074

Answers (4)

Kashyap Vijay
Kashyap Vijay

Reputation: 1

file = request.FILES['file']

load_file = FileSystemStorage()

filename = load_file.save(file.name, file)  // saving in local directory and getting filename

data = {'name': name, 'address': address, 'age':age }

fr_data = None
with open(filepath ,'rb') as fr:
    fr_data += fr.read()

url = 'http://127.0.0.1:8000/api/'

response = requests.post(url=url, data=data, files= {
                          'filefiledname': fr_data
                          }
                         )

Upvotes: -1

ccamacho
ccamacho

Reputation: 739

It is actually working right now using Python's requests module

Ill put the code for all interested...

Django server...

urls.py

...
url(r'^list/$', 'dataports.views.list', name='list'),
...

views.py

@csrf_exempt
def list(request):
    # Handle file upload
    if request.method == 'POST':
        print "upload file----------------------------------------------"
        form = DocumentForm(request.POST, request.FILES)
        if form.is_valid():
            print "otra vez.. es valido"
            print request.FILES

            newdoc = Jobpart(
                                partfile = request.FILES['docfile']
            )
            newdoc.save()

            # Redirect to the document list after POST
            return HttpResponseRedirect(reverse('dataports.views.list'))
    else:
        #print "nooooupload file----------------------------------------------"
        form = DocumentForm() # A empty, unbound form


    # Render list page with the documents and the form
    return render_to_response(
        'data_templates/list.html',
        {'form': form},
        context_instance=RequestContext(request)
    )

list.html

<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <title>Minimal Django File Upload Example</title>   
    </head>

    <body>
        <!-- Upload form. Note enctype attribute! -->
        <form action="{% url "list" %}" method="post" enctype="multipart/form-data">
            <p>
                {{ form.docfile }}
            </p>
            <p><input type="submit" value="Upload" /></p>
        </form>

    </body>

</html>

Now in the client.

client.py

import requests
url = "http://localhost:8000/list/"
response = requests.post(url,files={'docfile': open('test.txt','rb')})

Now you are able to add some security and stuff.. But it is actually a very simple example..

Thank you all!!!!

Upvotes: 0

almalki
almalki

Reputation: 4775

Using requests:

with open('file') as f:
    requests.post('http://some.url/upload', data=f)

Upvotes: 1

Paulo Bu
Paulo Bu

Reputation: 29794

What you want to do is to send a POST request to the Django app sending a file within it.

You can use python's standard library httplib module or the 3rd party requests module.That last link posted shows how to post a multipart encoded file which is probably what you need.

Hope this helps!

Upvotes: 2

Related Questions